CODEWITHSUNDEEP
phppreg-replace
Carpy
Carpy

Reputation: 1074

PHP preg_replace first word (including special chars)

I have a string which would look something like this "1-1-2012 Something, Something"

How could i wrap the date section so the result would end up as <span>1-1-2012</span> Something, Something

Thanks

Upvotes: 0

Views: 1114

Answers (4)

Berry Langerak
Berry Langerak

Reputation: 18859

preg_replace( '~\d{1,2}-\d{1,2}-\d{4}~', '<span>$0</span>', '1-1-2012 Something something' );

The regular expression ~\d{1,2}-\d{1,2}-\d{4} looks for one or two integers, followed by -, followed by another one or two integers, followed by a -, followed by 4 integers, which matches both "1-1-2012" and "05-10-2012". It then replaces the match with <span>$0</span>, where $0 will be replaced with the date found.

Upvotes: 1

Ruslan Polutsygan
Ruslan Polutsygan

Reputation: 4461

check this:

$str="1-1-2012 Something, Something";
$str=preg_replace('/\d-\d-\d{4}/', '<span>$0</span>', $str);
echo $str;

UPD

I missed that the first part was date :)

This might be used:

$str=preg_replace('/(:?\d{1,2}-){2}\d{4}/', '<span>$0</span>', $str);

Upvotes: -1

Baba
Baba

Reputation: 95121

You can try

$str = "11-10-2012 Something, Something";
$str = preg_replace("/\d{1,2}-\d{1,2}-\d{4}/", '<span>$0</span>', $str);
var_dump($str);

Output

 string '<span>4-10-2012</span> Something, Something' (length=43)

Upvotes: 1

Niet the Dark Absol
Niet the Dark Absol

Reputation: 324650

You could use something like this:

list($a,$b) = explode(" ",$input,2);
$out = "<span>".$a."</span> ".$b;

Upvotes: 4

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