CODEWITHSUNDEEP
javascriptarraysstringjoinsafari
Cole
Cole

Reputation: 1503

why does my array.join() not work as expected?

Safari 6:

> ['a=23', 'b=234', 'c=23'].join('&');
"a=23&b=234&c=23"

then with a variable I need to do this with. it's

jsss
  [
  Array[8]
    0: "s=1"
    1: "l=NTA4NTQzNnw0NzczOTg"
    2: "r=-1"
    3: "t=a"
    4: "m=0"
    5: "si=5156695"
    6: "u=5085436"
    7: "sn=mip"
    length: 8
    __proto__: Array[0]
   ]

> jsss.join('&');
"s=1,l=NTA4NTQzNnw0NzczOTg,r=-1,t=a,m=0,si=5156695,u=5085436,sn=mip"

Why does it seem to ignore the separator?

Upvotes: 5

Views: 3069

Answers (2)

Matt Whipple
Matt Whipple

Reputation: 7134

It looks like you have an array with a nested array, so you're only calling join on the top array which only has one element (the child array) and therefore just echoes that array with default behavior and nothing to delimit.

Upvotes: 12

Musa
Musa

Reputation: 97672

There is only one item in the jsss array so there is no use for the separator. I think what you want is jsss[0].join('&');

Upvotes: 6

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