CODEWITHSUNDEEP
linuxarraysgrep
Sam
Sam

Reputation: 2347

Storing one line of grep output per array element

If you perform a grep command with multiple lines, and multiple words per line, the output seems to be stored in an array by word rather than by line. How can you change it so that it's stored per line?

For example:

first_title=( $(egrep -o 'class\=\"title\" title\=\"'.\{1,80\} index.html
| egrep -o title\=\".*\"\> | sed 's/title\=\"//g' | sed 's/">//g') )


echo ${first_title[0]}

If this returned 10 lines, and the first read "This is a line"

It would only output "This"

Upvotes: 2

Views: 1669

Answers (2)

Vaughn Cato
Vaughn Cato

Reputation: 64308

You can use IFS to change the field separator:

IFS='
'
first_title=( $(egrep -o 'class\=\"title\" title\=\"'.\{1,80\} index.html
| egrep -o title\=\".*\"\> | sed 's/title\=\"//g' | sed 's/">//g') )


echo ${first_title[0]}
unset IFS

Upvotes: 3

Gilles Quénot
Gilles Quénot

Reputation: 185035

If you want to add an element with spaces, then you need to quote it like in the following example :

arr=( "this is a line" "this is another line" this is some words )
echo "${arr[0]}"
this is a line
printf '%s\n' "${arr[@]}"
this is a line
this is another line
this
is
some
words

So in your case, try something like that :

first_title=(
    $(
        egrep -o 'class\=\"title\" title\=\"'.\{1,80\} index.html |
            egrep -o title\=\".*\"\> |
            sed 's/title\=\"//g;
                s/">//g;
                s/.*/"&"/'
    )
)


echo "${first_title[0]}"

Upvotes: 0

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