CODEWITHSUNDEEP
pythonlist
Anthony Lee
Anthony Lee

Reputation: 59

Easiest way to check if list element in other list element?

    a = ['ava','olivia','hannah','olivia']
    b = ['aa','ab','ac','av']

    for i in a:
        for j in b:
            if j in i:
                print (i)
    #output: ava


    for i in a:
        if any(j in i for j in b):
            print (i)
    #output: ava

There are 2 lists with some elements, I want to the if each list 2 elements in each list 1 elements.

There are any better way to get it?

Upvotes: 0

Views: 67

Answers (2)

Tim
Tim

Reputation: 20777

This is enough:

print [word for word in a if any(part in word for part in b)]

No need to use filter, map or lambda.

Upvotes: 5

andrean
andrean

Reputation: 6796

Not necessarily better, but they're oneliners:

a = ['ava','olivia','hannah','olivia']
b = ['aa','ab','ac','av']

result = filter(None, map(lambda x: x if any(map(lambda y: y in x, b)) else None, a))
print result

or:

result2 = filter(None, [x if y in x else None for x in a for y in b])
print result3

or:

result3 = filter(None, [x if any([y in x for y in b]) else None for x in a])
print result2

Upvotes: 0

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