Reputation: 1969
I'm trying to get the int value of a text file that have text like:
123456789 12345678 1234567 123456 12345 1234 123 12 1
as you can see every number is different and they are in a same line separated by a "space". I need to get the values separated. to get something like this:
INT1 = 123456789, INT2 = 12345678, INT3 = 1234567;
and so on. I don't create the text so I don't know how much numbers and groups they are, but they are always separated by a "space". I know how to read it. This is how I'm reading it:
try {
TEST1 = new BufferedReader(new FileReader("/sdcard/test.txt")).readLine();
} catch (NumberFormatException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
TEST.setText(""+scaling_available_frequencies);
and I got this output
194208 776175 958253 767883 700246 243663 966618 345199 945363 459833
NOTE: This is just a test.txt that I created to see if it works. The current code will ask the user for entering path and file name.
Now how can I set them to a variable per group?
Thanks
Upvotes: 1
Views: 1335
Reputation: 658
This is one way to parse the String to an integer array:
public int[] toIntArray( String stringFromFile ){
String[] allStrings = stringFromFile.split( "\\s" );
int[] intArray = new int[allStrings.length];
for( int i = 0; i < allStrings.length; ++i ){
try{
intArray[i] = Integer.parseInt( allStrings[i] );
}catch( NumberFormatException e ){
// Do whatever you think is appropriated
intArray[i] = -1;
}
}
return intArray;
}
Hope this helps.
Upvotes: 2
Reputation: 859
I believe readLine() get you String. You will need to use the Split() method of String and pass in the regularExpression (whitespace).
then you will need to use Integer.parseInt( ) method and pass in every string to parse them into Integer. you also need a loop to do the parse until nothing left
Upvotes: 1