Reputation: 4304
I have a table with records like this:
id timestamp dose drug_id
1 2012-10-04 09:10:54 05 2
1 2012-10-04 09:12:34 15 2
1 2012-10-04 09:15:12 20 2
1 2012-10-04 09:35:32 25 2
1 2012-10-04 09:37:34 25 2
1 2012-10-04 09:39:24 25 2
1 2012-10-04 09:42:16 35 2
1 2012-10-04 09:43:07 35 2
What I want to do is select the last 5 used dose values for a given drug, so in this case the query should return 35, 25, 20, 15, 05.
I know I can use TOP and ORDER BY to get the latest 5 entries, but in this case it would return duplicates (35, 35, 25, 25, 25).
What should I use to get the output I want?
Upvotes: 6
Views: 10033
Reputation: 4171
Will this help
DECLARE @T TABLE(ID INT,Time_Stamp DATETIME,Dose INT, Drug_Id INT)
INSERT INTO @T VALUES
(1,'2012-10-04 09:10:54',05,2),
(1,'2012-10-04 09:12:34', 15,2),
(1,'2012-10-04 09:15:12',20,2),
(1,'2012-10-04 09:35:32',25,2),
(1,'2012-10-04 09:37:34',25,2),
(1,'2012-10-04 09:39:24',25,2),
(1,'2012-10-04 09:42:16',35,2),
(1,'2012-10-04 09:43:07',35,2)
;WITH CTE AS(
SELECT *, Rn = ROW_NUMBER()OVER(PARTITION BY Dose ORDER BY Time_Stamp DESC)
FROM @T)
SELECT TOP 5 ID,Time_Stamp,Dose,Drug_Id
FROM CTE
WHERE Rn = 1
ORDER BY Dose DESC
Upvotes: 3
Reputation: 2467
SELECT top 5 dose
FROM table_id
GROUP BY dose
ORDER BY max(timestamp) desc
Upvotes: 3
Reputation: 633
I don't have access to my server to test this, but should not
SELECT TOP 5 dose
FROM table_id
GROUP BY dose
ORDER BY max(time) desc;
work?
EDIT: Tested on http://sqlfiddle.com/#!6/610c4/2, note that I haven't used timestamp
merely time
. Fix appropriately.
Upvotes: 12