Reputation: 22772
Are there other ways to increment a for
loop in Javascript besides i++
and ++i
? For example, I want to increment by 3 instead of one.
for (var i = 0; i < myVar.length; i+3) {
//every three
}
Upvotes: 201
Views: 531843
Reputation: 8165
For those who are looking to increment pair of numbers (like 1-2 to 3-4):
Solution one:
//initial values
var n_left = 1;
var n_right = 2;
for (i = 1; i <= 5; i++) {
console.log(n_left + "-" + n_right);
n_left =+ n_left+2;
n_right =+ n_right+2;
}
//result: 1-2 3-4 5-6 7-8 9-10
Solution two:
for (x = 0; x <= 9; x+=2) {
console.log((x+1) + "-" + (x+2));
}
//result: 1-2 3-4 5-6 7-8 9-10
Upvotes: 2
Reputation: 21
There is an operator just for this. For example, if I wanted to change a variable i by 3 then:
var someValue = 9;
var Increment = 3;
for(var i=0;i<someValue;i+=Increment){
//do whatever
}
var someValue = 3;
var Increment = 3;
for(var i=9;i>someValue;i+=Increment){
//do whatever
}
Upvotes: 2
Reputation: 887
The last part of the ternary operator allows you to specify the increment step size. For instance, i++ means increment by 1. i+=2 is same as i=i+2,... etc. Example:
let val= [];
for (let i = 0; i < 9; i+=2) {
val = val + i+",";
}
console.log(val);
Expected results: "2,4,6,8"
'i' can be any floating point or whole number depending on the desired step size.
Upvotes: 2
Reputation: 2349
for (var i = 0; i < myVar.length; i+=3) {
//every three
}
additional
Operator Example Same As
++ X ++ x = x + 1
-- X -- x = x - 1
+= x += y x = x + y
-= x -= y x = x - y
*= x *= y x = x * y
/= x /= y x = x / y
%= x %= y x = x % y
Upvotes: 5
Reputation: 91149
A for
loop:
for(INIT; TEST; ADVANCE) {
BODY
}
Means the following:
INIT;
while (true) {
if (!TEST)
break;
BODY;
ADVANCE;
}
You can write almost any expression for INIT
, TEST
, ADVANCE
, and BODY
.
Do note that the ++
operators and variants are operators with side-effects (one should try to avoid them if you are not using them like i+=1
and the like):
++i
means i+=1; return i
i++
means oldI=i; i+=1; return oldI
Example:
> i=0
> [i++, i, ++i, i, i--, i, --i, i]
[0, 1, 2, 2, 2, 1, 0, 0]
Upvotes: 16
Reputation: 81
You certainly can. Others have pointed out correctly that you need to do i += 3
. You can't do what you have posted because all you are doing here is adding i + 3
but never assigning the result back to i
. i++
is just a shorthand for i = i + 1
, similarly i +=3
is a shorthand for i = i + 3
.
Upvotes: 2
Reputation: 66404
Andrew Whitaker's answer is true, but you can use any expression for any part.
Just remember the second (middle) expression should evaluate so it can be compared to a boolean true
or false
.
When I use a for
loop, I think of it as
for (var i = 0; i < 10; ++i) {
/* expression */
}
as being
var i = 0;
while( i < 10 ) {
/* expression */
++i;
}
Upvotes: 5
Reputation: 126072
Use the +=
assignment operator:
for (var i = 0; i < myVar.length; i += 3) {
Technically, you can place any expression you'd like in the final expression of the for loop, but it is typically used to update the counter variable.
For more information about each step of the for loop, check out the MDN article.
Upvotes: 386