CODEWITHSUNDEEP
bash
Juli Rio
Juli Rio

Reputation: 13

summing values of variables in bash

I'm trying to get all the regular files opened by all the processes in the current session. I have this code

while read pid
do

        FILES_ACTUAL=$(lsof -p $pid | grep REG | wc -l)   


done < <(ps -o pid,tt -u $USER | grep $CURRENT_TERMINAL | awk '{print $1}')

echo $FILES_ACTUAL

but I don't know how to add up, inside the while, the variable $FILES_ACTUAL.. I tried to use the awk command, but I couldn´t do it.

Upvotes: 0

Views: 129

Answers (2)

nsa
nsa

Reputation: 565

There is also a comand called expr which does simple arithmetic operations with integers and can be used like this:

expr $VAR1 + $VAR2

Upvotes: 0

phininity
phininity

Reputation: 1683

You can perform bash arithmetic by enclosing the statements inside (()):

NEW_FILES=$(lsof -p $pid | grep REG | wc -l)
((FILES_ACTUAL+=NEW_FILES))

Upvotes: 1

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