CODEWITHSUNDEEP
clinuxubuntu
lowcosthighperformance
lowcosthighperformance

Reputation: 151

compile and execute c program with argument

I am new in C program and linux, how can we compile and run this program?

I have tried gcc example.c then ./a.out but it gives an error like input file cannot be opened ( I have written this error in the read method)

// example.c
int main(int argc, char *argv[])
{
    char* input = argv[1];
    read(input);

    char* output = argv[2];
    write(output);

    return 0;
}

Thanks.

Upvotes: 2

Views: 21432

Answers (2)

Aniket Inge
Aniket Inge

Reputation: 25705

Firstly read() and write() both take 3 arguments(only one given).

Secondly it should be used like this:

int ifilehandle = open(argc[1],O_RDONLY,S_IREAD);
int ofilehandle = open(argc[2],O_WRONLY,S_IWRITE);
char buffer[32767];
read(ifilehandle,&buffer,32766);
write(ofilehandle,&buffer,32766);
close(ifilehandle);
close(ofilehandle);

Thirdly, a.out should be invoked like this:

./a.out filename1.extension filename2.extension

Upvotes: 1

Carl Norum
Carl Norum

Reputation: 224962

Your program isn't going to work very well - you're not providing enough arguments to read and write, for example (assuming you mean to be calling POSIX read(2) and write(2), that is).

To answer your actual question, the problem appears to be that you're not providing any arguments. You need to run it something like:

./a.out FILE1 FILE2

replacing FILE1 with the name of your input file and FILE2 with the name of your output file.

Upvotes: 3

Related Questions