CODEWITHSUNDEEP
phpyii
FaisalKhan
FaisalKhan

Reputation: 2496

Yii: To show Image in CGridView column based on database value

I am trying to show a ticked image if my value if set to Y. I followed this post but I get the following as contents of my grid column instead of the image:

<img src="/webapp/images/tickedS.jpg" alt="" />

Following is my model code for the new method that I wrote:

    public function getSurgeryFlaged(){
    return $this->flag_for_dashboard=='Y' ?  CHtml::image(Yii::app()->baseUrl .'/images/tickedS.jpg') : '';  

}

Following is column option for CGridView :

'SurgeryFlag'=>array('name'=>'Flag','value'=>'$data->surgeryFlaged','htmlOptions'=>array('width'=>'50')),

Instead of Model property, if I create a Controller protected method, the result is the same. Kindly guide, what am I doing wrong...?

Thanks in advance. Regards, Faisal

Upvotes: 0

Views: 3423

Answers (1)

Asgaroth
Asgaroth

Reputation: 4334

You should use 'raw' as the type. see CFormatter

raw: the attribute value will not be changed at all.

'SurgeryFlag'=>array(
   'type'=>'raw',
   'name'=>'Flag',
   'value'=>'$data->surgeryFlaged',
   'htmlOptions'=>array('width'=>'50')),

Upvotes: 1

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