Reputation: 3440
I am trying to encrypt the same data using C# and Java. If the data is more than 7 bytes then Java and C#'s encrypted value are not identical.
Input 1: a
java output: FrOzOp/2Io8=
C# output: FrOzOp/2Io8=
Input 2: abc
j : H9A/ahl8K7I=
c#: H9A/ahl8K7I=
Input 3: aaaaaaaa (Problem)
j : Gxl7e0aWPd7j6l7uIEuMxA==
c#: Gxl7e0aWPd7sf1xR6hK4VQ==
Here is the implementation of C# and Java methods.
C# code:
public String saltTxt = "12345678";
public String Encrypt(String txt)
{
byte[] data = Encrypt(Encoding.UTF8.GetBytes(txt));
DESCryptoServiceProvider alg = new DESCryptoServiceProvider();
alg.Key = Encoding.UTF8.GetBytes(saltTxt.ToCharArray(), 0, cprovider.KeySize / 8);
alg.IV = new byte[8];
MemoryStream ms = new MemoryStream();
CryptoStream stem = new CryptoStream( ms, cprovider.CreateEncryptor(),CryptoStreamMode.Write);
stem.Write(txt, 0, txt.Length);
stem.FlushFinalBlock();
data = ms.ToArray();
return Convert.ToBase64String(data);
}
Java Code:
public String saltTxt = "12345678";
public String Encrypt(String str) {
try {
KeySpec myKey = new DESKeySpec(saltTxt.getBytes("UTF8"));
SecretKey key = SecretKeyFactory.getInstance("DES").generateSecret(myKey);
Cipher ecipher = Cipher.getInstance("DES");
ecipher.init(Cipher.ENCRYPT_MODE, key);
byte[] data = str.getBytes("UTF8");
byte[] crypt = ecipher.doFinal(data);
return new BASE64Encoder().encode(crypt);
} catch (Exception ex) {
}
return null;
}
Any idea why it's not working as expected?
Upvotes: 2
Views: 6068
Reputation: 3440
The problem was in mode
of encryption.
SunJCE provider uses
ECB
as the default mode, andPKCS5Padding
as the default padding scheme for DES, DES-EDE and Blowfish ciphers. (JCA Doc)
and
In
.Net
, The default operation mode for the symmetric algorithm isCipherMode.CBC
and default padding isPaddingMode.PKCS7
. (msdn..SymmetricAlgorithm)
The following changes resolve the problem.
// in C#
DESCryptoServiceProvider alg = new DESCryptoServiceProvider();
alg.Mode = CipherMode.ECB; // specified
or
// in java
chiper = Cipher.getInstance("DES/CBC/PKCS5Padding");
don't change in both sides.
Upvotes: 9
Reputation:
The code (Java/Android) bellow worke for me. I used the same approach on C#.
public static String Cripto(String Password)
{
String PasswordCripto = "";
try
{
String encryptionKey = "anyEncryptionString";
MessageDigest messageDigest = MessageDigest.getInstance("MD5");
messageDigest.update(encryptionKey.getBytes("UTF-8"), 0, encryptionKey.length());
byte[] encryptionKeyBytes = messageDigest.digest();
SecretKeySpec Key = new SecretKeySpec(encryptionKeyBytes,"DESede");
Cipher cipher = Cipher.getInstance("DESEDE/ECB/PKCS5Padding");
cipher.init(Cipher.ENCRYPT_MODE, Key);
byte[] encryptedBytes = cipher.doFinal(Password.getBytes("UTF-8"));
PasswordCripto = new String(Base64.encode(encryptedBytes, Base64.DEFAULT), "UTF-8");
} catch(Exception e) { }
return PasswordCripto ;
}
Upvotes: 0
Reputation: 887469
You're probably seeing ISO 10126 padding, which appends random bytes to the plaintext to fill it up t oa multiple of the block size.
This behavior is by design.
Upvotes: 1