CODEWITHSUNDEEP
pythonstring
user1631534
user1631534

Reputation: 15

parse string of numbers with +/- signs and keep signs

I have a string that looks like this

+0.6810+0.0266-0.0140-0.0111-0.0080-00.026-0.0229+000.84

I need to parse this string at each +/- sign and while at the same time keeping the signs with the numbers so that they can be stored into variables. So what I want to have come out are varialbes for each of seven positive or negative numbers like

a= 0.6810
b= 0.0266
c= -0.0140

etc

I am able to spit the string but now now a way converting to a flow and keeping the sign current code to split string is:

print (re.split(r'[+-]+',dataString))

Upvotes: 0

Views: 233

Answers (3)

Rohit Jain
Rohit Jain

Reputation: 213351

You can use re.findall on your string: -

>>> string = "+0.6810+0.0266-0.0140-0.0111-0.0080-00.026-0.0229+000.84"
>>> 
>>> import re
>>> matches = re.findall(r'[-+]\d+\.\d+', string)
>>> matches
['+0.6810', '+0.0266', '-0.0140', '-0.0111', '-0.0080', '-00.026', '-0.0229', 
 '+000.84']
>>>
>>> a = float(matches[0])
>>> 0.681

>>> (a, b, c, d, e, f, g) = map(float, matches)[:7]

Upvotes: 2

gonzofish
gonzofish

Reputation: 1417

What about a string replace with a split? Something like

print (re.replace(r"([+-])", " \1", dataString)).split()

Might not be the best way, but it'll do the job...I think, didn't test it!

Upvotes: 0

Bakuriu
Bakuriu

Reputation: 101999

If the string is like the one you posted you can simply do something like:

your_string.replace('-', '+-').split('+')

But this is not robust.

Anyway you could simply use the re.findall method. I think:

re.findall(r'[+-]\d+(\.\d+)?', your_string)

should do the trick.

Actually it would also match integers, if your numbers always have the period and digits on both sites you can use:

r'[+-]\d+\.\d+

Upvotes: 3

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