Reputation: 90475
I wrote this:
public static class EnumerableExtensions
{
public static int IndexOf<T>(this IEnumerable<T> obj, T value)
{
return obj
.Select((a, i) => (a.Equals(value)) ? i : -1)
.Max();
}
public static int IndexOf<T>(this IEnumerable<T> obj, T value
, IEqualityComparer<T> comparer)
{
return obj
.Select((a, i) => (comparer.Equals(a, value)) ? i : -1)
.Max();
}
}
But I don't know if it already exists, does it?
Upvotes: 182
Views: 307425
Reputation: 41090
Thankfully the language has added support for IEnumerable.Index() as of .NET 9 that returns an enumerable of ValueTuple like so: IEnumerable<(int Index, TSource Item)>
Example usage:
public class Program
{
public static void Main()
{
PrintIndexes([1, 2, 3, 4]);
}
public static void PrintIndexes(IEnumerable<int> collection)
{
foreach(var (index, item) in collection.Index())
{
System.Console.WriteLine($"{index}: {item}");
}
}
}
Output:
0: 1
1: 2
2: 3
3: 4
You'd use .Index()
to simplify the answer from Marc Gravell like this:
public static int IndexOf<T>(this IEnumerable<T> source, T value)
{
var comparer = EqualityComparer<T>.Default; // or pass in as a parameter
foreach (var (index, item) in source.Index())
{
if (comparer.Equals(item, value))
return index;
}
return -1;
})
Upvotes: -1
Reputation: 318
You can add a small extension method:
public static IEnumerable<(T value, int index)> Index<T>(this IEnumerable<T> source)
=> source.Select((x, i) => (value: x, index: i));
And then you can use it like:
// get the index of a particular element
myCollection.Index().First(x => x.value == myElement).index;
// loop through elements with indices
foreach (var (element, i) in myCollection.Index()) {
// do whatever
}
// get the original index of the 3rd item that matches some criteria
myCollection.Index().Where(/* some condition */).ElementAt(2).index
Upvotes: 1
Reputation: 79
Try this:
static int FindIndex<T>(this IEnumerable<T> a, Predicate<T> f) =>
a.TakeWhile(x => !f(x)).Count();
static int IndexOf<T>(this IEnumerable<T> a, T value) =>
a.FindIndex(x => EqualityComparer<T>.Default.Equals(x, value));
var i = new[] { 1, 2, 3 }.IndexOf(2); // 1
Upvotes: -2
Reputation: 3017
Stumbled across this today in a search for answers and I thought I'd add my version to the list (No pun intended). It utlises the null conditional operator of c#6.0
IEnumerable<Item> collection = GetTheCollection();
var index = collection
.Select((item,idx) => new { Item = item, Index = idx })
//or .FirstOrDefault(_ => _.Item.Prop == something)
.FirstOrDefault(_ => _.Item == itemToFind)?.Index ?? -1;
I've done some 'racing of the old horses' (testing) and for large collections (~100,000), worst case scenario that item you want is at the end, this is 2x faster than doing ToList().FindIndex()
. If the Item you want is in the middle its ~4x faster.
For smaller collections (~10,000) it seems to be only marginally faster
Heres how I tested it https://gist.github.com/insulind/16310945247fcf13ba186a45734f254e
Upvotes: 4
Reputation: 9180
This can get really cool with an extension (functioning as a proxy), for example:
collection.SelectWithIndex();
// vs.
collection.Select((item, index) => item);
Which will automagically assign indexes to the collection accessible via this Index
property.
Interface:
public interface IIndexable
{
int Index { get; set; }
}
Custom extension (probably most useful for working with EF and DbContext):
public static class EnumerableXtensions
{
public static IEnumerable<TModel> SelectWithIndex<TModel>(
this IEnumerable<TModel> collection) where TModel : class, IIndexable
{
return collection.Select((item, index) =>
{
item.Index = index;
return item;
});
}
}
public class SomeModelDTO : IIndexable
{
public Guid Id { get; set; }
public string Name { get; set; }
public decimal Price { get; set; }
public int Index { get; set; }
}
// In a method
var items = from a in db.SomeTable
where a.Id == someValue
select new SomeModelDTO
{
Id = a.Id,
Name = a.Name,
Price = a.Price
};
return items.SelectWithIndex()
.OrderBy(m => m.Name)
.Skip(pageStart)
.Take(pageSize)
.ToList();
Upvotes: 0
Reputation: 13910
The best way to catch the position is by FindIndex
This function is available only for List<>
Example
int id = listMyObject.FindIndex(x => x.Id == 15);
If you have enumerator or array use this way
int id = myEnumerator.ToList().FindIndex(x => x.Id == 15);
or
int id = myArray.ToList().FindIndex(x => x.Id == 15);
Upvotes: 8
Reputation: 121
A few years later, but this uses Linq, returns -1 if not found, doesn't create extra objects, and should short-circuit when found [as opposed to iterating over the entire IEnumerable]:
public static int IndexOf<T>(this IEnumerable<T> list, T item)
{
return list.Select((x, index) => EqualityComparer<T>.Default.Equals(item, x)
? index
: -1)
.FirstOr(x => x != -1, -1);
}
Where 'FirstOr' is:
public static T FirstOr<T>(this IEnumerable<T> source, T alternate)
{
return source.DefaultIfEmpty(alternate)
.First();
}
public static T FirstOr<T>(this IEnumerable<T> source, Func<T, bool> predicate, T alternate)
{
return source.Where(predicate)
.FirstOr(alternate);
}
Upvotes: 5
Reputation: 1916
A bit late in the game, i know... but this is what i recently did. It is slightly different than yours, but allows the programmer to dictate what the equality operation needs to be (predicate). Which i find very useful when dealing with different types, since i then have a generic way of doing it regardless of object type and <T>
built in equality operator.
It also has a very very small memory footprint, and is very, very fast/efficient... if you care about that.
At worse, you'll just add this to your list of extensions.
Anyway... here it is.
public static int IndexOf<T>(this IEnumerable<T> source, Func<T, bool> predicate)
{
int retval = -1;
var enumerator = source.GetEnumerator();
while (enumerator.MoveNext())
{
retval += 1;
if (predicate(enumerator.Current))
{
IDisposable disposable = enumerator as System.IDisposable;
if (disposable != null) disposable.Dispose();
return retval;
}
}
IDisposable disposable = enumerator as System.IDisposable;
if (disposable != null) disposable.Dispose();
return -1;
}
Hopefully this helps someone.
Upvotes: 5
Reputation: 764
The way I'm currently doing this is a bit shorter than those already suggested and as far as I can tell gives the desired result:
var index = haystack.ToList().IndexOf(needle);
It's a bit clunky, but it does the job and is fairly concise.
Upvotes: 27
Reputation: 886
An alternative to finding the index after the fact is to wrap the Enumerable, somewhat similar to using the Linq GroupBy() method.
public static class IndexedEnumerable
{
public static IndexedEnumerable<T> ToIndexed<T>(this IEnumerable<T> items)
{
return IndexedEnumerable<T>.Create(items);
}
}
public class IndexedEnumerable<T> : IEnumerable<IndexedEnumerable<T>.IndexedItem>
{
private readonly IEnumerable<IndexedItem> _items;
public IndexedEnumerable(IEnumerable<IndexedItem> items)
{
_items = items;
}
public class IndexedItem
{
public IndexedItem(int index, T value)
{
Index = index;
Value = value;
}
public T Value { get; private set; }
public int Index { get; private set; }
}
public static IndexedEnumerable<T> Create(IEnumerable<T> items)
{
return new IndexedEnumerable<T>(items.Select((item, index) => new IndexedItem(index, item)));
}
public IEnumerator<IndexedItem> GetEnumerator()
{
return _items.GetEnumerator();
}
IEnumerator IEnumerable.GetEnumerator()
{
return GetEnumerator();
}
}
Which gives a use case of:
var items = new[] {1, 2, 3};
var indexedItems = items.ToIndexed();
foreach (var item in indexedItems)
{
Console.WriteLine("items[{0}] = {1}", item.Index, item.Value);
}
Upvotes: 1
Reputation: 139
I think the best option is to implement like this:
public static int IndexOf<T>(this IEnumerable<T> enumerable, T element, IEqualityComparer<T> comparer = null)
{
int i = 0;
comparer = comparer ?? EqualityComparer<T>.Default;
foreach (var currentElement in enumerable)
{
if (comparer.Equals(currentElement, element))
{
return i;
}
i++;
}
return -1;
}
It will also not create the anonymous object
Upvotes: 13
Reputation: 77520
I would implement it like this:
public static class EnumerableExtensions
{
public static int IndexOf<T>(this IEnumerable<T> obj, T value)
{
return obj.IndexOf(value, null);
}
public static int IndexOf<T>(this IEnumerable<T> obj, T value, IEqualityComparer<T> comparer)
{
comparer = comparer ?? EqualityComparer<T>.Default;
var found = obj
.Select((a, i) => new { a, i })
.FirstOrDefault(x => comparer.Equals(x.a, value));
return found == null ? -1 : found.i;
}
}
Upvotes: 33
Reputation: 42516
The whole point of getting things out as IEnumerable is so you can lazily iterate over the contents. As such, there isn't really a concept of an index. What you are doing really doesn't make a lot of sense for an IEnumerable. If you need something that supports access by index, put it in an actual list or collection.
Upvotes: 59
Reputation: 1062745
I'd question the wisdom, but perhaps:
source.TakeWhile(x => x != value).Count();
(using EqualityComparer<T>.Default
to emulate !=
if needed) - but you need to watch to return -1 if not found... so perhaps just do it the long way
public static int IndexOf<T>(this IEnumerable<T> source, T value)
{
int index = 0;
var comparer = EqualityComparer<T>.Default; // or pass in as a parameter
foreach (T item in source)
{
if (comparer.Equals(item, value)) return index;
index++;
}
return -1;
}
Upvotes: 152