CODEWITHSUNDEEP
javagson
Raveesh Sharma
Raveesh Sharma

Reputation: 1486

Gson : Unable to invoke no-args constructor for class

Although there are several threads on this topic.. please do not mark this as duplicate.

My pojo looks like this : 

public class sample {


    public sample() {
        // TODO Auto-generated constructor stub
    }

    private String instructions;
    private String resource;
    private List<Map<String,String>> fields;
    private String taskid;

    private List<Map<String,String>> answer;

    public String getTaskid() {
        return taskid;
    }
    public void setTaskid(String taskid) {
        this.taskid = taskid;
    }
    public String getInstructions() {
        return instructions;
    }
    public void setInstructions(String instructions) {
        this.instructions = instructions;
    }
    public String getResource() {
        return resource;
    }
    public void setResource(String resource) {
        this.resource = resource;
    }
    public List<Map<String,String>> getFields() {
        return fields;
    }
    public void setFields(List<Map<String,String>> fields) {
        this.fields = fields;
    }
    public List<Map<String,String>> getAnswer() {
        return answer;
    }
    public void setAnswer(List<Map<String,String>> answer) {
        this.answer = answer;
    }



}

I am doing a httpget and the result is an array of Json objects I try to typecast it to sample but it gives an exception.

the deserialization snippet is as follows

sample[] temp = gsonObj.fromJson(response, sample[].class);

the exception i get is 

java.lang.RuntimeException: Unable to invoke no-args constructor for class [sample;. Register an InstanceCreator with Gson for this type may fix this problem.
    at com.google.gson.MappedObjectConstructor.constructWithAllocators(MappedObjectConstructor.java:68)
    at com.google.gson.MappedObjectConstructor.construct(MappedObjectConstructor.java:52)
    at com.google.gson.JsonObjectDeserializationVisitor.constructTarget(JsonObjectDeserializationVisitor.java:42)
    at com.google.gson.JsonDeserializationVisitor.getTarget(JsonDeserializationVisitor.java:60)
    at com.google.gson.ObjectNavigator.accept(ObjectNavigator.java:104)
    at com.google.gson.JsonDeserializationContextDefault.fromJsonObject(JsonDeserializationContextDefault.java:76)
    at com.google.gson.JsonDeserializationContextDefault.deserialize(JsonDeserializationContextDefault.java:54)
    at com.google.gson.Gson.fromJson(Gson.java:551)
    at com.google.gson.Gson.fromJson(Gson.java:498)
    at com.google.gson.Gson.fromJson(Gson.java:467)
    at com.google.gson.Gson.fromJson(Gson.java:417)
    at com.google.gson.Gson.fromJson(Gson.java:389)
    at HTTPClientUtils.getResultsFromMobileWorks(HTTPClientUtils.java:327)

Can you please let me know where i am making the mistake ??

Upvotes: 4

Views: 19112

Answers (2)

paul
paul

Reputation: 13471

You have to use TypeToken class from Google.
You will need of course has a generic class T to make it works, like below:

Type fooType = new TypeToken<Foo<Bar>>() {}.getType();

gson.fromJson(json, fooType);

Upvotes: 0

Nishant
Nishant

Reputation: 55866

Can't reproduce. But here what works:

public class Sample {

    public Sample(){}
    public int kk;
    public List<Map<String,String>> fields;


    public static void main(String[] args) {
        String s = "[{\"kk\":1, \"fields\":[{\"a\":\"a1\"}]}, {\"kk\":5}, {\"kk\":2}, {\"kk\":8}, {\"kk\":6, \"fields\":[{\"b\":\"b1\"}]}]";
        Sample[] r = new Gson().fromJson(s, Sample[].class);
        for(Sample t: r)
            System.out.println(">> " + t.kk + " " + t.fields);
    }

}

results:

>> 1 [{a=a1}]
>> 5 null
>> 2 null
>> 8 null
>> 6 [{b=b1}]

Sidenote:

  1. Capitalize your classes, always.
  2. post a sscce

Upvotes: 2

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