Reputation: 1677
Using SQL Server 2005.
I have a table with calendar months
Month, fiscalorder
june,1
july,2
..
may,12
And another table with employees and a repeating monthly amount
employee, month, amount
john, july, 10
john, july, 3
john, august,2
mary, june, 2
mary, feb, 5
I need to join and aggregate these by month, but every month (even months without data) to report for every employe, but employee then fiscal order.
Output:
june, john, 0
july, john, 13
august,john,2
sept, john, 0
..
june,mary,2
Upvotes: 1
Views: 332
Reputation: 11773
SELECT month,employee,SUM(amount) amount
FROM(
SELECT m.month, e.employee, ISNULL(s.amount, 0) AS amount
FROM dbo.months AS m
CROSS JOIN (SELECT DISTINCT employee FROM dbo.sales) AS e
LEFT JOIN dbo.sales AS s
ON s.employee = e.employee
AND m.month = s.month
)X
GROUP BY month, employee
Upvotes: 1
Reputation: 4171
Assuming Sql Server 2005+
Declare @CalenderMonths Table ([Month] Varchar(20),FiscalOrder Int)
Insert Into @CalenderMonths Values
('June',1),('July',2),('August',3),('September',4),('October',5),('November',6),
('December',7),('January',8),('February',9),('March',10),('April',11),('May', 12)
Declare @Employee Table(employee varchar(50), [month] Varchar(20), amount int )
Insert Into @Employee Values('john', 'July', 10),('john', 'July',3),('john','August',2),('mary','June',2),('mary', 'February',5)
;with cte as
(
Select employee,[month],TotalAmount = sum(amount)
from @Employee
group by employee,[month]
)
select x.[Month],x.employee,amount = coalesce(c.TotalAmount,0)
from (
select distinct c.[Month],e.employee
from @CalenderMonths c cross join cte e)x
left join cte c on x.[Month] = c.[Month] and x.employee = c.employee
order by 2
Upvotes: 1