Reputation: 1813
A reporting service generates a csv file and certain columns (oddly enough) have mixed date/time format , some rows contain datetime expressed as m/d/y, others as d.m.y
When applying =TYPE() it will either return 1 or 2 (Excel will recognize either a text or a number (the Excel timestamp))
How can I convert any kind of wrong date-time format into a "normal" format that can be used and ensure some consistency of data?
I am thinking of 2 solutions at this moment :
Thanks
Upvotes: 1
Views: 1062
Reputation: 15923
If you can't get the data changed then you may have to resort to another column that translates the dates: (assumes date you want to change is in A1)
=IF(ISERR(DATEVALUE(A1)),DATE(VALUE(RIGHT(A1,LEN(A1)-FIND(".",A1,4))),VALUE(MID(A1,FIND(".",A1)+1,2)),VALUE(LEFT(A1,FIND(".",A1)-1))),DATEVALUE(A1))
it tests to see if it can read the text as a date, if it fails, then it will chop up the string, and convert it to a date, else it will attempt to read the date directly. Either way, it should convert it to a date you can use
Upvotes: 1
Reputation: 336468
Certainly your second option is the way to go in the medium-to-long term. But if you need a solution now, and if you have access to a text editor that supports Perl-compatible regular expressions (like Notepad++, UltraEdit, EditPad Pro etc.), you can use the following regex:
(^|,)([0-9]+)/([0-9]+)/([0-9]+)(?=,|$)
to search for all dates in the format m/d/y
, surrounded by commas (or at the start/end of the line).
Replace that with
\1\3.\2.\4
and you'll get the dates in the format d.m.y
.
Upvotes: 1