Reputation: 60691
I have a working query that gives me the maxdate:
SELECT a.client_id AS client_id
, a.patientcount AS patientcount
, received_date AS maxRecDate
FROM
(
SELECT DISTINCT CLIENT_ID
, PATIENT_ID
, count(*) over (partition by client_id, patient_id) AS patientcount
from f_accession_daily
) AS a
JOIN F_ACCESSION_DAILY AS f ON a.CLIENT_ID = f.CLIENT_ID
AND a.PATIENT_ID = f.PATIENT_ID
GROUP BY f.RECEIVED_DATE, a.CLIENT_ID, a.patientcount
HAVING f.RECEIVED_DATE = MAX(f.received_date)
In the same query I would also like to return min(f.received_date).
Is there a way to do this? perhaps with the subquery?
Upvotes: 0
Views: 3804
Reputation: 863
In your query, add an OR condition to check for MIN date as well. Solves the problem
SELECT a.client_id AS client_id
, a.patientcount AS patientcount
, received_date AS maxRecDate
FROM
(
SELECT DISTINCT CLIENT_ID
, PATIENT_ID
, count(*) over (partition by client_id, patient_id) AS patientcount
from f_accession_daily
) AS a
JOIN F_ACCESSION_DAILY AS f ON a.CLIENT_ID = f.CLIENT_ID
AND a.PATIENT_ID = f.PATIENT_ID
GROUP BY f.RECEIVED_DATE, a.CLIENT_ID, a.patientcount
HAVING f.RECEIVED_DATE = MAX(f.received_date)
OR f.RECEIVED_DATE = MIN(f.received_date) -- Newly added condition
Upvotes: 1
Reputation: 40506
I might be missing something, but I don't see why you are grouping by f.RECEIVED_DATE
I think the query could be:
SELECT a.client_id AS client_id
, a.patientcount AS patientcount
, max(f.received_date) AS maxRecDate
, min(f.received_date) AS minRecDate
FROM
(
SELECT DISTINCT CLIENT_ID
, PATIENT_ID
, count(*) over (partition by client_id, patient_id) AS patientcount
from f_accession_daily
) AS a
JOIN F_ACCESSION_DAILY AS f ON a.CLIENT_ID = f.CLIENT_ID
AND a.PATIENT_ID = f.PATIENT_ID
GROUP BY a.CLIENT_ID, a.patientcount
I haven't tested this, but I think it should work.
Upvotes: 2