CODEWITHSUNDEEP
c++templatesspecialization
pingw33n
pingw33n

Reputation: 12520

Function template specialization with reference to pointer

I have a template function:

template<typename T>
void foo(const T& value) { bar(value); x = -1; }

I want to specialize it for a set of types:

template<>
void foo<char>(const char& value) { bar(value); x = 0; }
template<>
void foo<unsigned char>(const unsigned char& value) { bar(value); x = 1; }

It works ok. When I compile this:

template<>
void foo<char*>(const char*& value) { bar(value); x = 2; }

I get an error:

error C2912: explicit specialization; 'void foo(const char *&)' is not a specialization of a function template

Is it possible to specialize with char* pointer type parameter without typedef'ing it?

Upvotes: 12

Views: 7387

Answers (2)

UncleBens
UncleBens

Reputation: 41351

You should generally just avoid function template specializations: you'll have far less problems if you provide non-template overloads instead. Read more: Why Not Specialize Function Templates?

Upvotes: 3

C. K. Young
C. K. Young

Reputation: 223193

Sure. Try this:

template<>
void foo<char*>(char* const& value) {...}

This is because const char* means pointer to const char, not a const pointer to char.

Upvotes: 20

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