CODEWITHSUNDEEP
pythonlist
Sreeni Puthiyillam
Sreeni Puthiyillam

Reputation: 485

how to search or find a particular substring in a list

value = ["python:guru-age20",
         "is_it_possible_time100:goodTime99",
         "hmm_hope_no_onecanansswer"]

How to get a particular string from this list of strings? I need to find goodTime99 from the li[1] string and its exact postion

if value.find("goodTime99") != -1: I know will work if I give the entire string is_it_possible_time100:goodTime99.

Otherwise how to exact the position by searching goodTime99 instead of searching for is_it_possible_time100:goodTime99? value.index("goodTime99") is giving an error.

I am not looking for whole string to search, value.index("is_it_possible_time100:goodTime99") is fine but I don't want this. Anyway to do this?

Upvotes: 2

Views: 205

Answers (4)

avasal
avasal

Reputation: 14854

if you want a single line answer you can have

In [339]: [value.index(x) for x in value if x.find("goodTime99") > -1]
Out[339]: [1]

simplest way could be :

it will give you all the index's of the strings containing your substring from the list

In [334]: value = ["python:guru-age20",
   .....:          "is_it_possible_time100:goodTime99",
   .....:          "hmm_hope_no_onecanansswer"]

In [335]: indexs = []

In [336]: for x in value:
   .....:     if x.find("goodTime99") > -1:
   .....:         indexs.append(value.index(x))
   .....:

In [337]: print indexs
[1]

In [338]: int(*indexs)
Out[338]: 1

Upvotes: 2

chuchao333
chuchao333

Reputation: 1518

this will give you all the matches with also the indexes if you need:

filter(lambda x: x[1].find("goodTime99") != -1, enumerate(value))

if you want the indexes only, then

[e[0] for e in filter(lambda x: x[1].find("goodTime99") != -1, enumerate(value))]

for example, this is what I got:

>>> value = ["python:guru-age20", "is_it_possible_time100:goodTime99","hmm_hope_no_onecanansswer"]
>>> res = [e[0] for e in filter(lambda x: x[1].find("goodTime99") != -1, enumerate(value))]
>>> res
[1]

Upvotes: 1

Paolo Moretti
Paolo Moretti

Reputation: 55946

If you only want to check for the presence of "goodTime99" in any string in the list, you could try:

value = ["python:guru-age20", "is_it_possible_time100:goodTime99","hmm_hope_no_onecanansswer"]
if any("goodTime99" in s for s in value):
    # found it

If you need the exact position:

>>> next((i for i, s in enumerate(value) if "goodTime991" in s), -1)
1

or:

def find_first_substring(lst, substring):
    return next((i for i, s in enumerate(lst) if substring in s), -1)

>>> find_first_substring(value, "goodTime99")
1

Upvotes: 2

unwind
unwind

Reputation: 399703

You simply need to search through each individual string in turn:

for s in value:
  if s.find("goodTime99"):
     print "found in", s
     break

Upvotes: 0

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