Reputation: 323
I have been trying to get this array function to output (non-zero) minimum values in the 'FINAL DATA' AE column. Can you see a structural error in this formula?
=IF($C$4="All EMEA",
MIN(IF('FINAL DATA'!$2:$AE$250000<>0,
('FINAL DATA'!$J$2:$J$250000=$C$4)*('FINAL DATA'!$E$2:$E$250000=$E$4)*( 'FINAL DATA'!$AE$2:$AE$250000))),
MIN(IF('FINAL DATA'!$AE$2:$AE$250000<>0,
('FINAL DATA'!$K$2:$K$250000=$C$4)*('FINAL DATA'!$E$2:$E$250000=$E$4)*( 'FINAL DATA'!$AE$2:$AE$250000)))
)
Upvotes: 0
Views: 1634
Reputation: 53127
Barry has identified the core problem (tests returnimg 0 to the MIN function).
Here's a refactor of your formula (still an array formula) that solves this, and is quite a bit shorter
=MIN(IF(($S:$S<>0)*($E:$E=$E$4)*(IF($C$4="All EMEA",$J:$J,$K:$K)=$C$4),
($S:$S)))
Note that this (as would your original formaul, when fixed) will return 0
if there are no qualifying values >0 in the ranges
Upvotes: 1
Reputation: 9453
You can eliminate the zeros by using an IF()
function in an array formula. Consider the following:
A
Row -----
1 0
2 7
3 5
4 6
5
6 3
The array formula =MIN(IF($A$1:$A$6>0,$A$1:$A$6))
will return 3
because the 0
and blank cell are eliminated with the >0
portion of the if statement.
Upvotes: 0
Reputation: 46341
By using <>0 that will eliminate zeroes and blanks, so that isn't the problem.....[although if you only want to eliminate blanks and have zero as a valid return value you should use <>""]
You can't multiply the conditions with the number range because by multiplying you get zeroes for any rows where the conditions are not satisfied, use multiple IFs instead, like this:
=MIN(IF('FINAL DATA'!$AE$2:$AE$250000<>0,IF('FINAL DATA'!$J$2:$J$250000=$C$4,IF('FINAL DATA'!$E$2:$E$250000=$E$4,'FINAL DATA'!$AE$2:$AE$250000))))
Upvotes: 2
Reputation: 162
Second line, you have !$2, no column specified.
MIN(IF('FINAL DATA'!$2:$AE$250000<>0,
Also, it looks like you are trying to run a single If comparison against a range, which I don't think will work the way you are trying to use it.
Upvotes: 1