CODEWITHSUNDEEP
java
user1761325
user1761325

Reputation: 93

Java Initialize an array with numbers

6, 9

2, 5

4, 6

how to initialize these number in an 2D array?

this is my answer, but something with output.

int[][] num = new int [3][2];

    num[0][0] = 6;
    num[0][1] = 9;
    num[1][0] = 2;
    num[1][1] = 5;
    num[2][0] = 4;
    num[2][1] = 6;

System.out.println(num);

[[I@70f87478 (output)

Upvotes: 2

Views: 811

Answers (4)

MarioDS
MarioDS

Reputation: 13073

When you do

System.out.println(num);

You will print the object's default ´toString` method, which prints the object's reference. TO print the contents, you can use 2 nested for-loops or a for-each loop.

Upvotes: 0

Sergii Zagriichuk
Sergii Zagriichuk

Reputation: 5399

Logic like in deepToString

        int [][] test = new int[1][1];
        StringBuilder builder  = new StringBuilder();
        for (int[] ints : test) {
           builder.append(Arrays.toString(ints)); 
        }
        System.out.println(builder.toString());

Upvotes: 0

Jon Skeet
Jon Skeet

Reputation: 1504122

There's nothing wrong with that output, other than you're calling toString on array and expecting to get something useful. If you use Arrays.deepToString() instead, you'll get a more sensible result. (You'd normally only need Arrays.toString(), but you need the "deep" version as it's an array of arrays.)

Additionally, you can initialize the array more compactly. Combining the two:

import java.util.Arrays;

public class Test {

    public static void main(String[] args) {
        int[][] num = { { 6, 9 }, { 2, 5 }, { 4, 6 } };
        System.out.println(Arrays.deepToString(num));
    }
}

Output:

[[6, 9], [2, 5], [4, 6]]

Upvotes: 5

Grisha Weintraub
Grisha Weintraub

Reputation: 7996

int[][] num = {{6,9},{2,5},{4,6}}
System.out.println(Arrays.deepToString(num));

Upvotes: 1

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