Reputation: 9766
I am trying to draw border in one side only to ImageButton
object,
like in CSS: border-left: 2px solid black;
.
Is there any way to do that with style only? (Without inserting a blank view between them)
Thank you!
EDIT:
I used the <selector>
tag with the ImageButton
.
Upvotes: 2
Views: 1859
Reputation: 9766
After alot of searching, I found way to do that.
Create xml file that containce the border style (border_style.xml):
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item>
<shape xmlns:android="http://schemas.android.com/apk/res/android"android:shape="rectangle">
<!-- The border color -->
<solid android:color="#000" />
</shape>
</item>
<item android:left="1dp">
<shape xmlns:android="http://schemas.android.com/apk/res/android"android:shape="rectangle">
<!-- The fill color-->
</shape>
</item>
</layer-list>
then in the selector, you write like that:
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:state_pressed="true">
<!-- Press Event -->
</item>
<item android:state_focused="true">
<!-- Focuse Event -->
</item>
<item android:drawable="@drawable/border_style.xml" />
</selector>
Upvotes: 3
Reputation: 6201
You do not able to do like css. You need to create a xml and put the xml in android drable folder and send the image-button background
And rectangle drawable back.xml (put into res/drawable folder):
<shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle" >
<solid android:color="#ffffff" />
<stroke android:width="1dip" android:color="#4fa5d5"/>
</shape>
Upvotes: 0