Reputation: 12999
I've a situation that is like this contrived example:
template<class TFeature> struct Controller {};
template<class TController,typename T> struct Feature {
typedef Feature<TController,T> FeatureType;
};
typedef Controller<Feature::FeatureType,int> DefaultController;
The Controller is templated to accept features and my problem is that some of the features need the type of the controller as a template parameter. This makes the typedef on the last line of the sample not compile.
Is this possible or do I need to rethink the design?
Upvotes: 5
Views: 1321
Reputation: 6914
In order to accomplish this you should do some meta programming magic(and believe me it is not an easy task). But if you really nead it and using boost
is an option for you take a look at boost::mpl
and you can have something like this:
template< class ControlerT >
struct FeatureEx {
typedef ControlerT controler_type;
};
template< class FeatureT >
struct ControlerEx {
typedef ControlerEx<FeatureT> this_type;
typedef typename boost::mpl::apply<
FeatureT, boost::mpl::identity<this_type>
>::type feature_type;
feature_type const& get_feature() const {return f_;}
private:
feature_type f_;
};
typedef ControlerEx<FeatureEx<boost::mpl::placeholders::_1> > DefaultControler;
Upvotes: 2
Reputation: 18368
Seems that you're trying to pass 2 params to you Controller template, while it can accept only one.
Upvotes: 0
Reputation: 9063
You are passing to the Controller
class two template parameters, but you have declared it to take only one. Do you need something like the following?
typedef Controller<Feature<Controller<int>,int>::FeatureType> DefaultController;
Upvotes: 1
Reputation: 231273
One option would be to use a dummy subclass instead of a typedef:
struct DefaultController : public Controller<Feature<DefaultController,int>::FeatureType> {};
Upvotes: 0