CODEWITHSUNDEEP
phpfilesessioninclude
BackSlash
BackSlash

Reputation: 22233

Pass $_SESSION variables to included file

i have a first PHP file: /home/www/subdomain1.domain.tld/file.php

<?php
    session_start();
    $_SESSION['foo']='bar';   
    include "/home/www/subdomain2.domain.tld/foo2.php";
 ?>

and /home/www/subdomain2.domain.tld/foo2.php:

<?php 
    session_start();
    echo $_SESSION['foo'];
?>

The "include" in the first file generates a "500 Internal Server Error", i think it's because session variables are not passed to included files, how can i fix that?

Thank you Alex

EDIT: I must use session variables in order to use these variables on every php file on subdomain2.

Upvotes: 0

Views: 997

Answers (2)

drew010
drew010

Reputation: 69937

You shouldn't be starting the session in the second file. Since the session was started in file.php, it is already available to foo2.php.

The error may be because PHP output a warning that the session was already started.

For debugging, add error_reporting(E_ALL); ini_set('display_errors', 1); to the beginning of your first PHP script.

You should just be able to do:

file.php

<?php
    session_start();
    $_SESSION['foo']='bar';   
    include "/home/www/subdomain2.domain.tld/foo2.php";

foo2.php

i have a first PHP file: /home/www/subdomain1.domain.tld/file.php

and /home/www/subdomain2.domain.tld/foo2.php:

<?php 
// session_start();  // remove, do not need this here
echo $_SESSION['foo'];

Upvotes: 0

noetix
noetix

Reputation: 4923

You don't need to use sessions when including a file. It is all the same request with the same namespace.

file.php:

$foo = 'bar';

include 'foo2.php';

foo2.php

echo $foo; // returns 'bar'

Upvotes: 0

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