Reputation: 16499
How can I read the first line from a text file using a Windows batch file? Since the file is large I only want to deal with the first line.
Upvotes: 102
Views: 395008
Reputation: 5780
Here is a workaround using powershell
:
powershell (Get-Content file.txt)[0]
(You can easily read also a range of lines with powershell (Get-Content file.txt)[0..3]
)
If you need to set a variable inside a batch script as the first line of file.txt
you may use:
for /f "usebackq delims=" %%a in (`powershell ^(Get-Content file.txt^)[0]`) do (set "head=%%a")
To test it create a text file test.txt
with at least a couple of lines and in the same folder run the following batch file (give to the file the .bat
extension):
@echo off
for /f "usebackq delims=" %%a in (`powershell ^(Get-Content test.txt^)[0]`) do (set "head=%%a")
echo Hello
echo %head%
echo End
pause
In the command prompt window that will open, provided that the content of first line of test.txt
is line 1
, you will see
Hello
line 1
End
Press any key to continue . . .
Upvotes: 2
Reputation: 3673
Print 1st line only (no need to read entire file):
set /p a=< file.txt & echo !a!
To print one line at a time; user to press a key for next line:
(After printing required lines, press Ctrl+C to stop.)
for /f "delims=" %a in (downing.txt) do echo %a & pause>nul
To print 1st n lines (without user intervention):
type nul > tmp & fc tmp "%file%" /lb %n% /t | find /v "?" | more +2
Tested on Win 10 CMD.
Upvotes: -1
Reputation: 61
powershell Get-Content file.txt -Head 1
This one is much quicker than the other powershell examples above, where the full file is read.
Upvotes: 6
Reputation: 777
In Windows PowerShell below cmd can be used to get the first line and replace it with a static value
powershell -Command "(gc txt1.txt) -replace (gc txt1.txt)[0], 'This is the first line' | Out-File -encoding ASCII txt1.txt"
Reference
How can you find and replace text in a file using the Windows command-line environment?
Upvotes: 0
Reputation: 21
To cicle a file (file1.txt
, file1[1].txt
, file1[2].txt
, etc.):
START/WAIT C:\LAERCIO\DELPHI\CICLADOR\dprCiclador.exe C:\LAERCIUM\Ciclavel.txt
rem set/p ciclo=< C:\LAERCIUM\Ciclavel.txt:
set/p ciclo=< C:\LAERCIUM\Ciclavel.txt
rem echo %ciclo%:
echo %ciclo%
And it's running.
Upvotes: 2
Reputation: 264
The problem with the EXIT /B
solutions, when more realistically inside a batch file as just one part of it is the following. There is no subsequent processing within the said batch file after the EXIT /B
. Usually there is much more to batches than just the one, limited task.
To counter that problem:
@echo off & setlocal enableextensions enabledelayedexpansion
set myfile_=C:\_D\TEST\My test file.txt
set FirstLine=
for /f "delims=" %%i in ('type "%myfile_%"') do (
if not defined FirstLine set FirstLine=%%i)
echo FirstLine=%FirstLine%
endlocal & goto :EOF
(However, the so-called poison characters will still be a problem.)
More on the subject of getting a particular line with batch commands:
How do I get the n'th, the first and the last line of a text file?" http://www.netikka.net/tsneti/info/tscmd023.htm
[Added 28-Aug-2012] One can also have:
@echo off & setlocal enableextensions
set myfile_=C:\_D\TEST\My test file.txt
for /f "tokens=* delims=" %%a in (
'type "%myfile_%"') do (
set FirstLine=%%a& goto _ExitForLoop)
:_ExitForLoop
echo FirstLine=%FirstLine%
endlocal & goto :EOF
Upvotes: 1
Reputation: 19
Another way
setlocal enabledelayedexpansion
@echo off
for /f "delims=" %%i in (filename.txt) do (
if 1==1 (
set first_line=%%i
echo !first_line!
goto :eof
))
Upvotes: 1
Reputation: 21281
Try this
@echo off
setlocal enableextensions enabledelayedexpansion
set firstLine=1
for /f "delims=" %%i in (yourfilename.txt) do (
if !firstLine!==1 echo %%i
set firstLine=0
)
endlocal
Upvotes: 3
Reputation: 17846
Here's a general-purpose batch file to print the top n
lines from a file like the GNU head
utility, instead of just a single line.
@echo off
if [%1] == [] goto usage
if [%2] == [] goto usage
call :print_head %1 %2
goto :eof
REM
REM print_head
REM Prints the first non-blank %1 lines in the file %2.
REM
:print_head
setlocal EnableDelayedExpansion
set /a counter=0
for /f ^"usebackq^ eol^=^
^ delims^=^" %%a in (%2) do (
if "!counter!"=="%1" goto :eof
echo %%a
set /a counter+=1
)
goto :eof
:usage
echo Usage: head.bat COUNT FILENAME
For example:
Z:\>head 1 "test file.c"
; this is line 1
Z:\>head 3 "test file.c"
; this is line 1
this is line 2
line 3 right here
It does not currently count blank lines. It is also subject to the batch-file line-length restriction of 8 KB.
Upvotes: 52
Reputation: 2629
uh? imo this is much simpler
set /p texte=< file.txt
echo %texte%
Upvotes: 249
Reputation: 638
You might give this a try:
@echo off
for /f %%a in (sample.txt) do (
echo %%a
exit /b
)
edit Or, say you have four columns of data and want from the 5th row down to the bottom, try this:
@echo off
for /f "skip=4 tokens=1-4" %%a in (junkl.txt) do (
echo %%a %%b %%c %%d
)
Upvotes: 13
Reputation: 2638
Uh you guys...
C:\>findstr /n . c:\boot.ini | findstr ^1:
1:[boot loader]
C:\>findstr /n . c:\boot.ini | findstr ^3:
3:default=multi(0)disk(0)rdisk(0)partition(1)\WINNT
C:\>
Upvotes: 26
Reputation: 648
Note, the batch file approaches will be limited to the line limit for the DOS command processor - see What is the command line length limit?.
So if trying to process a file that has any lines more that 8192 characters the script will just skip them as the value can't be held.
Upvotes: 0
Reputation: 16499
Thanks to thetalkingwalnut with answer Windows batch command(s) to read first line from text file I came up with the following solution:
@echo off
for /f "delims=" %%a in ('type sample.txt') do (
echo %%a
exit /b
)
Upvotes: 6
Reputation: 26715
One liner, useful for stdout redirect with ">":
@for /f %%i in ('type yourfile.txt') do @echo %%i & exit
Upvotes: 3
Reputation: 15015
Slightly building upon the answers of other people. Now allowing you to specify the file you want to read from and the variable you want the result put into:
@echo off
for /f "delims=" %%x in (%2) do (
set %1=%%x
exit /b
)
This means you can use the above like this (assuming you called it getline.bat)
c:\> dir > test-file
c:\> getline variable test-file
c:\> set variable
variable= Volume in drive C has no label.
Upvotes: 4