Reputation: 1799
I have 3 elements, two on the same level, and one child, all having fixed position. I need to set the z-index properties to place the parent on the bottom, the element on the same level in the middle, and the child on top.
I've tried setting a higher z-index for the child, but it's not working.
<div class="red">
<div class="blue"></div>
</div>
<div class="green"></div>
Here is the case http://jsfiddle.net/udENm/21/ (I need red
on the bottom, green
in the middle and blue
on top, still maintaining red
and green
on the same level).
My CSS is like this
.red {
position: fixed;
z-index: 2;
}
.green {
position: fixed;
z-index: 2;
}
.blue {
position: fixed;
z-index: 5;
}
Upvotes: 0
Views: 280
Reputation: 27549
The z-index
property only has effect within the stacking context of the containing element.
Put another way, given a bunch of block elements within the same parent element, you can control their front to back ordering pretty easily. However, z-index
can only control the front to back ordering within this parent element and not within the global context.
So, you can move .blue
backwards and forwards within .red
all you like. You can also switch .red
and .green
around in the z-plane all you like too. However, you can't put .green
between .red
and .blue
because they are in different stacking contexts.
EDIT
Stacking context only applies to elements that are in the flow. If you use position:absolute
, then you can do this. See Rick Calder's answer
Upvotes: 2
Reputation: 7811
Kinda like this?
HTML
<div class="foo">
<div class="child"></div>
<div class="bar"></div>
</div>
CSS
.foo {
background: red;
position: fixed;
left: 50px;
top: 50px;
z-index: 2;
width: 100px;
height: 100px;
}
.bar {
background: green;
position: fixed;
left: 100px;
top: 100px;
z-index: 5;
width: 100px;
height: 100px;
}
.child {
background: blue;
position: fixed;
left: 90px;
top: 90px;
z-index: 6;
width: 50px;
height: 50px;
}
Upvotes: 0
Reputation: 1989
The green blocks z-index needs to be lower than the red ones. I used this CSS instead of the one you posted:
.foo {
background: red;
position: fixed;
left: 50px;
top: 50px;
z-index: 2;
width: 100px;
height: 100px;
}
.bar {
background: green;
position: fixed;
left: 100px;
top: 100px;
z-index: 1;
width: 100px;
height: 100px;
}
.child {
background: blue;
position: absolute;
top:50%;
left:50%;
z-index: 5;
width: 50px;
height: 50px;
}
Works fine, as you can see green is now z-index 1, red is z-index 2 and the blue block has absolute positioning.
Upvotes: 1
Reputation: 2829
Z-index is relative in a way to the parent. Red is already at 2, and blue is only at z-index 5 compared to it's siblings, but not to outside elements like Green.
Each stacking context is self-contained: after the element's contents are stacked, the whole element is considered in the stacking order of the parent stacking context.
Upvotes: 0
Reputation: 18705
Set your positioning to absolute and remove the z-index from the parent div (the red one) entirely. http://jsfiddle.net/calder12/udENm/32/
.foo {
background: red;
position: absolute;
left: 50px;
top: 50px;
width: 100px;
height: 100px;
}
.bar {
background: green;
position: absolute;
left: 100px;
top: 100px;
z-index: 2;
width: 100px;
height: 100px;
}
.child {
background: blue;
position: absolute;
left: 40px;
top: 40px;
z-index: 5;
width: 50px;
height: 50px;
}
Upvotes: 2