CODEWITHSUNDEEP
python
user1050619
user1050619

Reputation: 20916

Popen execution error

This is how my code looks and I get an error, while using Popen

test.py

import subprocess
import sys

def test(jobname):
    print jobname
    p=subprocess.Popen([sys.executable,jobname,parm1='test',parm2='test1'])


if __name__ == "__main__":
   test(r'C:\Python27\test1.py')

test1.py

def test1(parm1,parm2):
  print 'test1',parm1

if __name__ = '__main__':
  test1(parm1='',parm2='')

Error

Syntax error

Upvotes: 0

Views: 136

Answers (1)

unutbu
unutbu

Reputation: 880987

In test1.py:

You need two equal signs in :

if __name__ = '__main__':

Use instead

if __name__ == '__main__':

since you want to compare the value of __name__ with the string '__main__', not assign a value to __name__.

In test.py:

parm1='test' is a SyntaxError. You can not to assign a value to a variable in the middle of a list:

p=subprocess.Popen([sys.executable,jobname,parm1='test',parm2='test1'])

It appears you want to feed different values for parm1 and parm2 into the function test1.test1. You can not do that by calling python test1.py since there parm1='' and parm2='' are hard-coded there.

When you want to run a non-Python script from Python, use subprocess. But when you want to run Python functions in a subprocess, use multiprocessing:

import multiprocessing as mp
import test1

def test(function, *args, **kwargs):
    print(function.__name__)
    proc = mp.Process(target = function, args = args, kwargs = kwargs)
    proc.start()
    proc.join()  # wait for proc to end

if __name__ == '__main__':
    test(test1.test1, parm1 = 'test', parm2 = 'test1')

Upvotes: 4

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