CODEWITHSUNDEEP
buttonseleniumclickcss-selectorswebdriver
user1769790
user1769790

Reputation: 1343

click() on css Selector not working in Selenium webdriver

HTML

<input class="button" type="button" onclick="$.reload('results')" value="Search">

I don't have an id or name for this . Hence am writing 

FirefoxDriver driver = new FirefoxDriver();
driver.get("http://....");
driver.findElement(By.cssSelector("input[value=Search]")).click();

But click() is not happening.

Tried driver.findElement(By.cssSelector(".button[value=Search]")).click();

Tried value='Search' (single quotes).

these Selectors are working in 

.button[value=Search] {
padding: 10px;
}
input[value=Search] {
padding: 10px;
}

Upvotes: 11

Views: 23219

Answers (4)

Amith
Amith

Reputation: 7008

single quotes are missing in your code, the [value=Search] should be replaced with [value='Search'].

first you have to check if the selector u are using will work or not..

If you are using chrome or FF,you can follow these steps,

  1. go to the page where button (to be clicked) is present,

  2. open web console and type in the following and click enter..

    $("input[value='Search']")

or

$("input[value='Search'][type='button']")

or

$("input[value='Search'][type='button'].button")

you will get a list of elements which can be accessed using this selector, if that list contains only one element (button that you want to click), then this selector is valid for your use..otherwise u'l have to try some other selector..

If any of the above selector is valid,u'l have to change your code accordingly..

driver.findElement(By.cssSelector("input[value='Search'][type='button'].button")).click();

Upvotes: 0

Jotish
Jotish

Reputation: 11

Please use the below code.

driver.findElement(By.cssSelector("input[value=\"Search\"]")).click();

It works for me. And make sure that the name is "Search", coz it is case sensitive.

Thanks

Upvotes: 1

Ioan
Ioan

Reputation: 5187

Are you sure that using this CSS-selector (input[value=Search]) on your page you have only one result?

Upvotes: 0

eugene.polschikov
eugene.polschikov

Reputation: 7339

i would inject piece of js to be confident in resolving this issue:

first of all locate element using DOM (verify in firebug): locating

public void jsClick(){

        JavascriptExecutor js = (JavascriptExecutor) driver;
        StringBuilder stringBuilder = new StringBuilder();
        stringBuilder.append("document.getElementsByTagName('button')[0].click();");
        js.executeScript(stringBuilder.toString());
    }
jsClick();

from the retrospective of your element it be like:

....
stringBuilder.append("document.getElementsByTagName('input')[0].click();");
....

Please, note: document.getElementsByTagName('input') returns you an array of DOM elements. And indexing it properly e.g. document.getElementsByTagName('input')[0], document.getElementsByTagName('input')1, document.getElementsByTagName('input')[2].... ,etc you will be able to locate your element.

Hope this helps you. Regards.

Upvotes: 2

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