CODEWITHSUNDEEP
c++regexstringvalidationboost
Larry Lee
Larry Lee

Reputation: 61

C++ Date Parsing Implementation

I'm currently working to parse dates into a program.

The format can be in the following form:

DDMMYYYY
DDMMYY
DDMM

DD/MM/YYYY
DD/MM/YY
DD/MM

Do that that along with the dates, there would be other content included such as the follows:

19/12/12 0800 1000

That breaks my current implementation of using boost::date_time and tokenizer.

For the situation, what would the best suggestion? Would I be able to have a better implementation that would allow the following:

19 Sep 12  // DD MMM YY

What I had in mind was to return them as strings in the form DDMMYYYY form for use in other parts of the program. Is this the best way or are there better suggestion/alternatives?

*EDIT:

Decided that taking DDMMYYYY, DDMMYY & DDMM isn't that feasible. Shall only go with dates with backslashes.

The output remains the same though, strings in the format : DDMMYYYY

Upvotes: 2

Views: 3383

Answers (3)

Pabitra Dash
Pabitra Dash

Reputation: 1513

The following code works for me.

regex regExDate("\\d{4}-\\d{2}-\\d{2}");
string date = "abc:\\2016-09-12";
smatch match;

if (regex_search(date, match, regExDate))
{
 string strDate = match.str();
}

Upvotes: 0

J.N.
J.N.

Reputation: 8421

Using boost.regex, you can do the following:

#include <iostream>
#include <boost/regex.hpp>

using namespace std;
using namespace boost;

int main(int argc, char* argv[])
{
    regex re("(\\d{2})\\/(\\d{2})(?:\\/?(\\d{2,4}))?");

    cmatch m;

    regex_search("1234 10/10/2012 4567", m, re);
    cout << m.str(1) + m.str(2) + m.str(3) << endl;
    regex_search("1234 10/10/12 4567", m, re);
    cout << m.str(1) + m.str(2) + m.str(3) << endl;
    regex_search("1234 10/10 4567", m, re);
    cout << m.str(1) + m.str(2) << endl;

    return 0;
}

Compile like this:

g++ --std=c++11 -o test.a test.cpp -I[boost_path] [boost_path]/stage/lib/libboost_regex.a

Upvotes: 2

Damask
Damask

Reputation: 1254

You can use some regexp library or builtin sscanf function. It is more primitive than reg exp but can be used in your case

/* sscanf example */
#include <stdio.h>

int main ()
{
   char sentence []="data 1";
   char str [16];
   int i;

   sscanf(sentence,"%s %d",str,&i);
   printf("%s -> %d\n",str,i);

 return 0;
}

Upvotes: 0

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