CODEWITHSUNDEEP
regexapache
onassar
onassar

Reputation: 3558

Regular expression to match string only if trailed by a character

I need help creating a regular expression. Here are two sample strings:

/path/to/file.jpg
/path/to/file.type.jpg

Respectively, I'm trying to capture:

file.jpg
file.type.jpg

But I want to capture the three as separate strings.

file,jpg
file,type,jpg

Note that I'm not capturing the periods. I thought something like this could work (excluding the new lines):

([a-z]+)\.
[([a-z]+)[\.]{1}]?
([a-z]{3})

Guidance would be appreciated. I'm wondering if there is another modified I would need to use to have it capture it properly.

The above expression errors out, by the way :(

Upvotes: 0

Views: 92

Answers (4)

Ωmega
Ωmega

Reputation: 43673

I suggest you to use pattern

\/([^.]+)\.?([^.]+|)\.([^.]+)$

and you will have 3 groups: file, type (which will be empty, if not present) and extension

Upvotes: 1

anubhava
anubhava

Reputation: 785196

This regex should work:

/(\w+)\.(\w+)(?:\.(\w+))?$/

Live Demo

Upvotes: 1

Javier Diaz
Javier Diaz

Reputation: 1830

You can use: "\/(?:\w+\/)+(\w+)\.?(\w+)?\.(\w+)" as regex.

Edit: didnt read about not matching dots.

Live Demo

Upvotes: 1

Matyas
Matyas

Reputation: 13702

You'd have to use: /(\w+)(\.(\w+))?\.(\w+){3,4}\b

Then capturing groups 1, 3 and 4 would be your: file(1) type(3) and jpg/png whatever(4)

Groups taken apart:

  1. (\w+) - matches word characters 1 or more (equivalent of saying: {1, }
  2. (\.(\w+))? - matches the 3rd group and with a dot in front, and makes the whole group optional ( ? )
  3. (\w+) - as gr 1
  4. (\w{3,4})\b - matchees 3 or 4 word characters ( {3,4} ) and ensures that after those chracters there are no other characters (word end - \b - ! if supported !)

Upvotes: 1

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