CODEWITHSUNDEEP
javascriptarraysfunction
user1745558
user1745558

Reputation: 91

javascript: pass an array to a function

here is my javascript code:

var my_array = new Array();
my_array[0] = "a";
my_array[0] = "b";
my_array[0] = "c";

print_array(my_array);

function print_array(arr)
{
   alert(arr);
}

But it doesn't work, because I can't pass the array to the function. So, how can I pass an entire array to javascript function?

EDIT: Nevermind. I found the solution.
Hidden cause this is bad practice and passes the array as a string:

If someone will need to pass an array to the function, first use this: JSON.stringify() and javascript will be able to parse an array.

Upvotes: 1

Views: 79046

Answers (8)

Fauzan DP
Fauzan DP

Reputation: 51

var my_array = ["a","b","c"];


function print_array(arr)
{
   alert(arr);
}

print_array(my_array);

Upvotes: 0

Thielicious
Thielicious

Reputation: 4452

var f=d=>
  d.forEach(k=>
    alert(k)
  );
let a=[1,2];
f(a);

fiddle

Upvotes: -2

ali.b.y
ali.b.y

Reputation: 67

Note this

function FollowMouse()
{
    var len = arguments.length;
    if(len == 0) return;
    //
    for(var i=0; i< len; i++)
    {
        arguments[i].style.top = event.clientY+"px";
        arguments[i].style.left = event.clientX+"px";
    }

};

//---------------------------

html page

<body onmousemove="FollowMouse(d1,d2,d3)">

<p><div id="d1" style="position: absolute;">Follow1</div></p>
<div id="d2" style="position: absolute;"><p>Follow2</p></div>
<div id="d3" style="position: absolute;"><p>Follow3</p></div>


</body>

can call function with any Args

<body onmousemove="FollowMouse(d1,d2)">

or

<body onmousemove="FollowMouse(d1)">

Upvotes: -2

roberkules
roberkules

Reputation: 6605

var my_array = ["a", "b", "c"];
// or a popular way to define (mainly string) arrays:
var my_array = "abc".split("");

print_array(my_array);

function print_array(arr) {
   alert(arr);
}

Upvotes: 0

codingbiz
codingbiz

Reputation: 26406

You were using the same index 0

var my_array = new Array();
my_array[0] = "a";
my_array[1] = "b";
my_array[2] = "c";

JS Fiddle

Upvotes: 0

Andreas Louv
Andreas Louv

Reputation: 47127

To extend Billy Moon's answer

You can define your array like this:

my_array = ["a", "b", "c"];

And like this:

my_array = [];
my_array[0] = "a";
// ...

Upvotes: 1

Billy Moon
Billy Moon

Reputation: 58619

The problem is you are assigning each element to index 0, so they are overwriting each other.

// should be
my_array[0] = "a";
my_array[1] = "b";
my_array[2] = "c";

// alternatively, if you don't want to track the index
my_array.push("a");
my_array.push("b");
my_array.push("c");

The rest of the code looks fine. You can pass whole arrays, or any object for that matter to a function in exactly the manner you have shown in your code.

When you alert it, javascript will concatenate the array into a comma separated string for easy viewing.

Upvotes: 9

jcolebrand
jcolebrand

Reputation: 16035

Try this code instead:

function print_array(arr)
{
   alert(arr);
}

var my_array = new Array();
my_array[0] = "a";
my_array[1] = "b";
my_array[2] = "c";

print_array(my_array);

You should define a function before you can call it as a good programming practice.

Also note the order of your elements that are being assigned, you're putting everything on 0, and they should be on 1, 2 etc.

Upvotes: 2

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