Reputation: 21
I'm having trouble making a script to replace a string that is inside double quotes. The files sections looks like this:
"regA~1" : "FF_NODE~94"
"regA~2" : "FF_NODE~105"
"regA~3" : "FF_NODE~116"
"regA~4" : "FF_NODE~127"
"regA~5" : "FF_NODE~138"
"regA~6" : "FF_NODE~149"
"regA~7" : "FF_NODE~154"
"regA~8" : "FF_NODE~155"
"regA~9" : "FF_NODE~156"
"regA~1" : "FF_NODE~95"
"regA~11" : "FF_NODE~96"
It works if I do
awk '/"regA~1"/{c++;if(c==2){sub("regA~1","regA~10");}}1' file > file_out
but when trying to make this a script where I pass a variable regA~1 and the value for c it doesn't work.
s="regA~1";
r="regA~10";
n=2;
awk -v search="$s" -v replace="$r" -v count=$n '/search/{c++;if(c==count){sub(search,replace);}}1' file > file_out
I also tried
awk -v search=$s -v replace=$r -v count=$n '/search/{c++;if(c==count){sub(search,replace);}}1' file > file_out
Upvotes: 2
Views: 962
Reputation: 21
Thanks to Ed Morton for the tip. Here's the bash script in case anyone needs something like this. Not very sophisticated but it works for me.
#!/bin/bash
# Replaces a specific occurrence of a search string with a replace string
if [ $# -lt 4 ] ; then
echo -e "Wrong number of parameters."
echo -e "Usage:"
echo -e "repnthstr file search replace n"
echo -e "repnthstr fileext search replace n"
exit 1
fi
for file in $1
do
if [ -f $file -a -r $file ]; then
awk -v search=$2 -v replace=$3 -v cnt=$4 '$0 ~ search{c++;if(c==cnt){sub(search,replace);}}1' "$file" > temp && mv temp "$file"
else
echo "Error: Cannot read $file"
fi
done
Upvotes: 0
Reputation: 203532
The syntax you need to match an RE that's stored as a string in a variable is
$0 ~ var
not
/var/
Upvotes: 1