Reputation: 535
138.096.000.015.00111-138.096.201.072.38717
138.096.000.015.01008-138.096.201.072.00790
138.096.201.072.00790-138.096.000.015.01008
138.096.201.072.33853-173.194.020.147.00080
138.096.201.072.34293-173.194.034.009.00080
138.096.201.072.38717-138.096.000.015.00111
138.096.201.072.41741-173.194.034.025.00080
138.096.201.072.50612-173.194.034.007.00080
173.194.020.147.00080-138.096.201.072.33853
173.194.034.007.00080-138.096.201.072.50612
173.194.034.009.00080-138.096.201.072.34293
173.194.034.025.00080-138.096.201.072.41741
I have many folders inside which there are many files, the file names are like the above I want to remove those files with file names having substring "138.096.000"
and sometimes I want to get the list of files with filenames with substring "00080"
Upvotes: 0
Views: 63
Reputation: 272307
rm $(find . -name \*138.096.000\*)
This uses the find command to find the appropriate files. This is executed within a subshell, and the output (the list of files) is used by rm
. Note the escaping of the * pattern, since the shell will try and expand *
itself.
This assumes you don't have filenames with spaces etc. You may prefer to do something like:
for i in $(find . -name \*138.096.000\*); do
rm $i
done
in this scenario, or even
find . -name \*138.096.000\* | xargs rm
Note that in the loop above you'll execute rm
for each file, and the xargs
variant will execute rm
multiple times (dependin gon the number of files you have - it may only execute once).
However, if you're using zsh then you can simply do:
rm **/*138.096.000*
(I'm assuming your directories aren't named like your files. Note the -f
flag as used in Kamil's answer if this is the case)
Upvotes: 0
Reputation: 2221
To delete files with name containing "138.096.000":
find /root/of/files -type f -name '*138.096.000*' -exec rm {} \;
To list files with names containing "00080":
find /root/of/files -type f -name '*00080*'
Upvotes: 1