Reputation: 480
I can find empirical distribution that way
select command_type, duration, round(percentage, 2)
from (select distinct command_type,duration_sec,
percent_rank() over(partition by command_type order by duration) percentage
from command_durations
order by 1, 2)
The question is how to do the same using oracle model clause. I have started with this
select command_type,duration,dur_count from command_durations
model UNIQUE SINGLE REFERENCE
partition by (command_type)
dimension by ( duration)
measures(0 dur_count)
rules(
dur_count[duration]=count(1)[cv(duration)]
)
order by command_type,duration
But now I need to make records distinct, in order to be able to proceed with finding empirical distribution.
How to do the records distinct in the model clause?
Upvotes: 2
Views: 165
Reputation: 457
If you want to take that query and use 'distinct' on it, one method might be to wrap that in a From Subquery statement, and then do a distinct. For instance:
Select Distinct command_type, duration, dur_count
From (
[Your Code]
)
Let me know if that works.
Upvotes: 1