Reputation: 35
I am using Visual Studio 2010 with Visual Basic. I have a dynamic 2 dimensional array that is coming into the function. I cannot figure out how to get the size of first row.
For example let say this array is passe into the function:
{{1, 0, 5, 4},
{8, 1, 4, 4},
{0, 1, 4, 4},
{7, 7, 7, 4},
{7, 7, 7, 4},
{8, 1, 4, 4}}
In this example I would get 4 because if you look at for example first row it has 4 elements. And for example in this case:
{{1, 0, 5, 4, 7, 7},
{8, 1, 4, 4, 7, 7},
{0, 1, 4, 4, 8, 8},
{7, 7, 7, 4, 3, 3},
{7, 7, 7, 4, 4, 4},
{8, 1, 4, 4, 1, 9}}
I would get back 6 cause rows have 6 elements in it. The array is coming in always 2d and rows are always the same length. Column size is unknown and row size in unknown. But if I find out row size for one row the all rows are that size if that makes sense.
I have tried this UBound(inArray, 1) but it does not work. Please help me figure this out.
Upvotes: 1
Views: 4521
Reputation: 39
To find the length of the x-axis, use the GetLength function. I have tried the GetUpperBound function and sometimes it has proven to be a little unreliable. Please use the code below as reference:
Dim array(1,10) As Double
Dim x as Integer = array.GetLength(0) - 1 'Will give you value of dimension x'
Upvotes: 0
Reputation: 5393
Dim i(,) As Integer = {{1, 0, 5, 4}, {8, 1, 4, 4}, {0, 1, 4, 4}, {7, 7, 7, 4}, {7, 7, 7, 4}, {8, 1, 4, 4}}
MsgBox(i.GetUpperBound(0)) 'first index
MsgBox(i.GetUpperBound(1)) 'second index
MsgBox(UBound(i, 1)) 'first index (UBOUND is 1-based)
MsgBox(UBound(i, 2)) 'second index (UBOUND is 1-based)
For the 2D array i(x,y)
, GetUpperBound(0)
returns the maximum value of x
, and GetUpperBound(1)
returns the maximum value of y
Upvotes: 1
Reputation: 166326
Have a look at using Array.GetUpperBound Method
Gets the upper bound of the specified dimension in the Array.
Upvotes: 2