CODEWITHSUNDEEP
c#genericscompiler-errorswarnings
Nick
Nick

Reputation: 10499

Generic - Compiler warning CS0693 or error

I have my generic class and two methods that accept as argument a delegate (generic or not)

public sealed class MyClass<TResult>
{
   public MyClass ContinueWith(ThreadInfo.Parameterized arg)
   {
   }

   public MyClass<TResult> ContinueWith<TResult>(ThreadInfo<TResult>.Parameterized arg)
   {
   }
}

Where:

public sealed class MyClass
{
}

I have the Compiler Warning (level3) CS0693 but if I remove <TResult> from the second method:

public MyClass<TResult> ContinueWith(ThreadInfo<TResult>.Parameterized arg)

I can't use this method anymore, if I try I get a compiler error because the compiler thinks I want to use the first method.

How can I solve this problem?

Upvotes: 0

Views: 1877

Answers (2)

Omar
Omar

Reputation: 16623

You have to use different parameter names. So this depends on what do you want to achieve.

I think you need something like this, where the return type is of type MyClass<TResult> and you can choose the type for ThreadInfo<>:

public MyClass<TResult> ContinueWith<T1>(ThreadInfo<T1>.Parameterized arg)
{
   //...
}

Or if you want to choose the type only when you create an instance of your object:

public MyClass<TResult> ContinueWith(ThreadInfo<TResult>.Parameterized arg)
{
   //...
}

Upvotes: 0

Jon Skeet
Jon Skeet

Reputation: 1499770

Well it sounds like you really want:

public MyClass<TResult> ContinueWith(ThreadInfo<TResult>.Parameterized arg)

In other words, using the TResult parameter declared at the type level.

If you really want it to be a generic method (i.e. introducing a new type parameter) you have to give it a different name:

public MyClass<T2> ContinueWith<T2>(ThreadInfo<T2>.Parameterized arg)

(It's possible that you may want to return a MyClass<TResult> here, or something similar - we don't really know what you're trying to achieve, which makes it hard to give detailed help.)

Upvotes: 3

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