Reputation: 1277
At the moment when I double/treble/etc click on the .next button the script is ran, I need it to queue after each other? How can I do this so that the function is completed before starting again?
HTML
<ul id="one" class="first selected">
<li class="pic_one"></li>
<li class="pic_two"></li>
<li class="pic_three"></li>
</ul>
<ul id="two">
<li class="pic_one"></li>
<li class="pic_two"></li>
<li class="pic_three"></li>
</ul>
<ul id="three" class="last">
<li class="pic_one"></li>
<li class="pic_two"></li>
<li class="pic_three"></li>
</ul>
jQuery
$('.slider .next').click(function(){
if($('.slider ul.selected').hasClass('last')){
// leave blank
} else {
$('.slider ul.selected').hide('slide', { direction: "left" }, 1000);
$('.slider ul.selected').removeClass('selected');
$('.slider ul').parent().next('ul').show('slide', { direction: "right" }, 1000).addClass('selected');
}
});
Upvotes: 4
Views: 4063
Reputation: 5929
If I understand your question properly...you're just trying to prevent animations from stacking on multiple clicks. Use .stop()
BEFORE calling your next animation.
Example:
$('.slider .next').click(function(){
if($('.slider ul.selected').hasClass('last')){
// leave blank
} else {
$('.slider ul.selected').stop().hide('slide', { direction: "left" }, 1000);
$('.slider ul.selected').removeClass('selected');
$('.slider ul').parent().next('ul').stop().show('slide', { direction: "right" }, 1000).addClass('selected');
}
});
Upvotes: 0
Reputation: 19740
Similar to Rory's answer, but using the :animated pseudoselector. This prevents the click event from being processed while the element is being animated.
$('.slider .next').click(function(){
if($('.slider ul.selected').is(':animated')) return;
if($('.slider ul.selected').hasClass('last')){
// leave blank
} else {
$('.slider ul.selected').hide('slide', { direction: "left" }, 1000);
$('.slider ul.selected').removeClass('selected');
$('.slider ul').parent().next('ul').show('slide', { direction: "right" }, 1000).addClass('selected');
}
});
Upvotes: 3