Reputation: 671
i want to exit my app with System.exit can anyone help me with any sample code? i am looking to achieve this when the back or home button is pressed.
Upvotes: 1
Views: 5351
Reputation: 2930
you can open dialog on back pressed override method like this.
@Override
public void onBackPressed() {
// TODO Auto-generated method stub
super.onBackPressed();
DialogInterface.OnClickListener dialogClickListener = new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
switch (which){
case DialogInterface.BUTTON_POSITIVE:
System.exit(0);
break;
case DialogInterface.BUTTON_NEGATIVE:
dialog.cancel();
break;
}
}
};
AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setMessage("Exit or not ?").setPositiveButton("Yes", dialogClickListener)
.setNegativeButton("No", dialogClickListener).show();
}
}
Upvotes: 1
Reputation: 47945
You simply need to add a onclick listener there you can execute the System.Exit
call:
((Button) findViewById(R.id.button)).setOnClickListener(new OnClickListener {
@Override
public void onClick(View v) {
System.Exit(0);
}
});
Upvotes: 0
Reputation: 9867
you can do it in back button like this
@Override
public void onBackPressed(){
super.onBackPressed();
System.exit(0)
}
Edit: If you are on first activity you dont need to do so, just press back button OS will close your app automatically
Upvotes: 0