Manas Saha
Manas Saha

Reputation: 1497

Regular expression to enforce 2 digits after decimal point

I need to validate a numeric string with JavaScript, to ensure the number has exactly two decimal places.

The validation will pass only if

  1. the number has precisely two decimal places
  2. there is at least one digit before the decimal point. (could be zero)
  3. the number before the decimal point can not begin with more than one zero.

Valid numbers:

0.01
0.12
111.23
1234.56
012345.67
123.00
0.00

Invalid numbers:

.12
1.1
0.0
00.00
1234.
1234.567
1234
00123.45
abcd.12
12a4.56
1234.5A

I have tried the regular expression [0-9][\.][0-9][0-9]$, but it allows letters before decimal point like 12a4.56.

Upvotes: 5

Views: 57242

Answers (7)

Mehul Velani
Mehul Velani

Reputation: 761

Try This Code

pattern="[0-9]*(\.?[0-9]{1,2}$)?"
  • 1 Valid

  • 1.1 Valid

  • 1.12 Valid

  • 1.123 not Valid

  • only number Valid

    pattern="[0-9]*(.?[0-9]{2}$)?"

  • 1 Valid

  • 1.1 not Valid

  • 1.12 Valid

  • 1.123 not Valid

  • only number Valid

Upvotes: 0

saurabh.khunt
saurabh.khunt

Reputation: 31

i used this

^[1-9][1-9]*[.]?[1-9]{0,2}$

  • 0 not accept

  • 123.12 accept but 123.123 not accept

  • 1 accept

  • 12213123 accept

  • sdfsf not accept

  • 15.12 accept

  • 15@12 not accept

  • 15&12 not accept

Upvotes: 3

phant0m
phant0m

Reputation: 16905

This covers all requirements:

^(0|0?[1-9]\d*)\.\d\d$
  • the number has precisely two decimal places
    • Trivially satisfied due to the non-optional \.\d\d$

The other two conditions can be restated as follows:

  • The number before the decimal points is either a zero
  • or a number with exactly one zero, then a number that does not start with zero

This is covered in these two cases:

  • 0
  • 0?[1-9]\d*

Upvotes: 7

Spudley
Spudley

Reputation: 168853

You don't need regular expressions for this.

JavaScript has a function toFixed() that will do what you need.

var fixedtotwodecimals = floatvalue.toFixed(2);

Upvotes: 4

Salvador Dali
Salvador Dali

Reputation: 222969

Here it is:

^(0[.]+\d{2})|^[1-9]\d+[.]+\d{2}$

Upvotes: 0

user529758
user529758

Reputation:

. matches any character, it does not do what you think it does. You have to escape it. Also, you have two more errors; try

^[0-9]+\.[0-9][0-9]$

instead, or even better, use \d for decimal digits:

^\d+\.\d\d$

Upvotes: 8

Man Programmer
Man Programmer

Reputation: 5356

var values='0.12';

document.write(values.match(/\d+[.]+\d+\d/));

change value as you want and check it

Upvotes: 1

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