Reputation: 1260
The following code is a section of one of my classes:
$stmt = $this->dbh->prepare("SELECT t_id FROM checkOut WHERE t_id = :param1");
$stmt->bindParam(':param1', $this->numberIn);
$stmt->execute();
$result = $stmt->fetch(PDO::FETCH_ASSOC);
var_dump($result);
$this->p_id = $result['p_id'];
My original issue was that php was stating that p_id
was an undefined index. To figure out what was going on, I threw in var_dump
to see what was in the array. For some reason, it contained only one value, 4
which corresponded to the first column's name, t_id
. My MySQL table has four columns, and I need all four to be present in the array. Why would my code only be grabbing the first column's value?
Any help would be appreciated.
Upvotes: 0
Views: 502
Reputation: 360572
You're only fetching one field:
SELECT t_id FROM checkOut ...
^^^^
if you want p_id, then you'll have to fetch that too:
SELECT p_id, t_id FROM checkOut
Upvotes: 2