Reputation:
I am confused on how to fill a vector with values from a different class.
Can anyone give me a coded example how this is done. :)
Class A
{
//vector is here
}
Class B
{
//add values to the vector here
}
main()
{
//access the vector here, and print out the values
}
I appreciate the help <3
Upvotes: 0
Views: 94
Reputation: 12514
You should make your question more specific, edit it and post what you've tried to do. If you mean to do something respecting oop-rules, the play looks like this:
#include<iostream>
#include<vector>
class A{
public:
void fill_up_the_vector() { v=std::vector<int>(3); v[0]=0; v[1]=1; v[2]=4; }
void add( a.add(i); ) { v.push_back(i); }
void display_last() const { std::cout<<v[v.size()-1]; }
private:
std::vector<int> v;
};
class B{
public:
B(){ a.fill_up_the_vector(); } // B just *instructs* A to fill up its vector.
void add_value(int i) { a.add(i); }
void display() const { a.display_last(); }
private:
A a;
};
int main()
{
B b;
b.add_value(9);
b.display(); // reads v through A.
}
Note that this example above is a bit different from what you've asked. I posted it since I think you sould keep in mind that according to OOP rules
The other way to go is not OOP:
struct A{
std::vector<int> v;
};
struct B{
static void fill_A(A& a) const { a.v = std::vector<int>(3); a.v[0]=0; a.v[1]=1; a.v[2]=4; }
};
int main()
{
A a;
B::fill_A(a);
a.v.push_back(9);
std::cout << a.v[a.v.size()-1];
}
but this code is as horrible as it gets.
Upvotes: 0
Reputation: 39148
My guess, based on the questions touch is that you're looking for the following code.
int main()
{
ClassA[] as = {new ClassA(), new ClassA(), ... }
ClassB[] bs = {new ClassB(), new ClassB(), ... }
}
But I'm shooting in the dark, a bit. :)
Upvotes: 0
Reputation: 10487
It seems like a quick lesson in access levels and encapsulation is in order.
Upvotes: 1