How to sort a hash by value in descending order and output a hash in ruby?

Question

output.sort_by {|k, v| v}.reverse

and for keys

h = {"a"=>1, "c"=>3, "b"=>2, "d"=>4}
=> {"a"=>1, "c"=>3, "b"=>2, "d"=>4}

Hash[h.sort]

Right now I have these two. But I'm trying to sort hash in descending order by value so that it will return

=> {"d"=>4, "c"=>3, "b"=>2, "a"=>1 }

Thanks in advance.

Edit: let me post the whole code.

def count_words(str)
  output = Hash.new(0)
  sentence = str.gsub(/,/, "").gsub(/'/,"").gsub(/-/, "").downcase
  words = sentence.split()
  words.each do |item|
    output[item] += 1 
  end
  puts Hash[output.sort_by{ |_, v| -v }]
  return Hash[output.sort_by{|k, v| v}.reverse]
end

Answer 1

Old question, but here are 2 other solutions, which are close, but found it more obvious when reading :

h = {"a"=>1, "c"=>3, "b"=>2, "d"=>4}

hash.sort_by(&:last).reverse # => [["d", 4], ["c", 3], ["b", 2], ["a", 1]]

hash.sort { |a,b| b.last <=> a.last }

Call to_h if you really need a hash instead of an array of arrays :

hash.sort_by(&:last).reverse.to_h # => {"d"=>4, "c"=>3, "b"=>2, "a"=>1}

hash.sort { |a,b| b.last <=> a.last }.to_h

Answer 2

Try this:

Hash[h.sort_by{ |_, v| -v }]

Answer 3

Try:

Hash[h.sort.reverse]

This should return what you want.

Edit:

To do it by value:

Hash[h.sort_by{|k, v| v}.reverse]