CODEWITHSUNDEEP
python
Alan Coromano
Alan Coromano

Reputation: 26008

Find a minimal value in each array in Python

Suppose I have the following data in Python 3.3:

my_array = 
   [{'man_id': 1, '_id': ObjectId('1234566'), 'type': 'worker', 'value': 11}, 
   {'man_id': 1, '_id': ObjectId('1234577'), 'type': 'worker', 'value': 12}],

   [{'man_id': 2, '_id': ObjectId('1234588'), 'type': 'worker', 'value': 11}, 
    {'man_id': 2, '_id': ObjectId('3243'), 'type': 'worker', 'value': 7},
    {'man_id': 2, '_id': ObjectId('54'), 'type': 'worker', 'value': 99},
    {'man_id': 2, '_id': ObjectId('9879878'), 'type': 'worker', 'value': 135}],
   #.............................
   [{'man_id': 13, '_id': ObjectId('111'), 'type': 'worker', 'value': 1}, 
    {'man_id': 13, '_id': ObjectId('222'), 'type': 'worker', 'value': 2},
    {'man_id': 13, '_id': ObjectId('3333'), 'type': 'worker', 'value': 9}]

There are 3 arrays. How do I find an element in each array with minimal value?

Upvotes: 1

Views: 345

Answers (2)

Artsiom Rudzenka
Artsiom Rudzenka

Reputation: 29103

Maybe something like that is acc for you:

for arr in my_array:
   minVal = min([row['value'] for row in arr])
   print [row for row in arr if row['value'] == minVal]

Upvotes: 1

Antimony
Antimony

Reputation: 39451

[min(arr, key=lambda s:s['value']) for arr in my_array]

Upvotes: 5

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