CODEWITHSUNDEEP
javafunctionexception
Mohit Sehgal
Mohit Sehgal

Reputation: 865

Function With No allowed Exceptions in Java

In C++ I can declare a function which can not further throw exceptions as under

int myfunction (int param) throw(); // no exceptions allowed

Can I have such declaration in Java programming language?

Upvotes: 1

Views: 140

Answers (3)

Joachim Sauer
Joachim Sauer

Reputation: 308131

No, any method can always throw an unchecked exception (RuntimeException and Error).

You only need to list checked exceptions (Exception subclasses that don't derive from RuntimeException) in the method declaration.

And an ugly side-note: while the compiler does check that no checked exception is thrown that is not declared, you can work around that with some ugly tricks (that's sometimes called a sneaky throw, Project Lombok supports it explicitly).

Upvotes: 5

Sumit Desai
Sumit Desai

Reputation: 1770

There's a way by which you can ensure that an exception will not at all be thrown to the previous layer. Simply put all your code in a try catch statement, so that even though any exception occurs in the method, it will always be catched.

But, remember it will only ensure that the exception will not propogate to the previous(calling) layer.It will surely not ensure that the exception will not at all occur in the method body

Upvotes: 0

Jakub Zaverka
Jakub Zaverka

Reputation: 8874

No, not in that sense. You can declare a function to not throw an exception (simply don't include the throws keyword), but you cannot prevent a function from throwing any exception at all. Imagine you will have division by zero in that function - the program's behaviour would be then undefined.

Upvotes: 0

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