CODEWITHSUNDEEP
javascriptregex
user1779868
user1779868

Reputation: 101

Regexp javascript

I need to edit my scrip to get only ref = '521590819123';

How ?

<script type="text/javascript">
var ref = "http://www.site.ru/profile/521590819123";
if( ref.indexOf('profile') >= 0 ) {
  ref = String(ref).substr(ref.indexOf('profile'));
}
alert(ref);
 </script>

Upvotes: 2

Views: 129

Answers (4)

Denys S&#233;guret
Denys S&#233;guret

Reputation: 382474

No need to use a regex :

var tokens = ref.split('/');
var whatyouwant = tokens[tokens.length-1];

Demonstration

If you really want to use a regex, you can do

var whatyouwant = /([^\/]+$)/.exec(ref)[0];

Demonstration

Upvotes: 2

Damask
Damask

Reputation: 1254

if you want to resolve this task by regexp, use:

 ref = ref.replace(/^.*\/(\d+)$/g, "$1")

Upvotes: 0

nfechner
nfechner

Reputation: 17545

Use lastIndexOf:

<script type="text/javascript">
  var ref = "http://www.site.ru/profile/521590819123";
  if( ref.indexOf('profile') >= 0 ) {
    ref = ref.substr(ref.lastIndexOf('/') + 1);
  }
  alert(ref);
</script>

See here: http://jsfiddle.net/CFeVV/

Upvotes: 0

Ahmad
Ahmad

Reputation: 12737

Just change indexof to LastIndexOf

ref = String(ref).substr(ref.lastIndexOf('/')+1);

Upvotes: 0

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