Reputation: 1336
A bit of a weird question but I was wondering anyone could help...
In C++, I could do something like this
class MyOtherClass
{
private:
MyLogger* logger;
public:
MyOtherClass (MyLogger* logger)
: logger (logger)
{}
};
class MyClass
{
private:
MyLogger* logger;
public:
MyClass (MyLogger* logger)
: logger (logger)
{}
};
int main (int c, char** args)
{
MyLogger* logger = new MyLogger ();
/* Code to set up logger */
MyOtherClass* myOtherClass = new MyOtherClass (logger);
MyClass* myClass = new MyClass (logger);
}
So that each of the other objects (myOtherClass and myClass) would contain a pointer to logger, so they would be calling the same logger class. However, how would I achieve the same thing in C#? Is there a way to store a reference or pointer to a global object - I'm guessing that in C# if I do something like
public class MyClass
{
private MyLogger logger = null;
public MyClass (MyLogger _logger)
{
logger = _logger;
}
};
that its actually assigning the class variable logger to a copy of _logger? Or am I'm mixing things up :S
Any help is very much appreciated, and thank you in advance!
Upvotes: 16
Views: 51856
Reputation: 783
adding comment for future me as sometime I also forget, also for someone new in c# want to visualize "c++ pointer" vs "c# object reference" vs "C# object reference By Ref". Notice how Passing By Ref(Last method call) and assigning new obj, changes original object.
using System;
public class Emp
{
public int TimeSpentInCompany {get; set;}
}
public class Program
{
public static void Main()
{
Emp t1 = new Emp{TimeSpentInCompany = 5};
Console.WriteLine("original obj before method call-->" + t1.TimeSpentInCompany);
// Test is one by one
// var res = PassObject_SimpleUpdateMemberAndPrint(t1);
// var res = PassObject_SimpleUpdateObjectAndPrint(t1);
// var res = PassObjectByRef_SimpleUpdateMemberAndPrint(ref t1);
var res = PassObjectByRef_SimpleUpdateObjectAndPrint(ref t1);
Console.WriteLine("original obj after method call-->" + t1.TimeSpentInCompany);
Console.WriteLine("obj from method response-->" + res.TimeSpentInCompany);
}
static Emp PassObject_SimpleUpdateMemberAndPrint(Emp data)
{
/*
original obj before method call-->5
in method before modification obj member--> 5
in method AFTER modification obj member--> 9
original obj after method call-->9
obj from method response-->9
*/
Console.WriteLine("in method before modification obj member--> "+ data.TimeSpentInCompany);
data.TimeSpentInCompany += 4;
Console.WriteLine("in method AFTER modification obj member--> "+ data.TimeSpentInCompany);
return data;
}
static Emp PassObject_SimpleUpdateObjectAndPrint(Emp data)
{
/*
original obj before method call-->5
in method before assigning new obj --> 5
in method AFTER assigning new obj --> 9
original obj after method call-->5
obj from method response-->9
*/
Console.WriteLine("in method before assigning new obj --> "+ data.TimeSpentInCompany);
data = new Emp{TimeSpentInCompany = 9};
Console.WriteLine("in method AFTER assigning new obj --> "+ data.TimeSpentInCompany);
return data;
}
static Emp PassObjectByRef_SimpleUpdateMemberAndPrint(ref Emp data)
{
/*
original obj before method call-->5
in method before modification obj member--> 5
in method AFTER modification obj member--> 9
original obj after method call-->9
obj from method response-->9
*/
Console.WriteLine("in method before modification obj member--> "+ data.TimeSpentInCompany);
data.TimeSpentInCompany += 4;
Console.WriteLine("in method AFTER modification obj member--> "+ data.TimeSpentInCompany);
return data;
}
static Emp PassObjectByRef_SimpleUpdateObjectAndPrint(ref Emp data)
{
/*
original obj before method call-->5
in method before assigning new obj --> 5
in method AFTER assigning new obj --> 9
original obj after method call-->9
obj from method response-->9
*/
Console.WriteLine("in method before assigning new obj --> "+ data.TimeSpentInCompany);
data = new Emp{TimeSpentInCompany = 9};
Console.WriteLine("in method AFTER assigning new obj --> "+ data.TimeSpentInCompany);
return data;
}
}
Upvotes: 0
Reputation: 37660
If the type is a reference type (which is the case for classes), then you will copy the reference, not the object itself.
In opposition to reference type, you have value types. Values types are basically basic types : int
, double
, etc,
In your case, that means that you will work with the same objects, whether you access it from the class, or from the outer calling method. It's because you are targeting the referenced object.
Upvotes: 2
Reputation: 63340
You're mixing things up. In C#, assignment statements such as
logger = _logger;
copy references, not objects. After this statement executes, there is still (at most) only one MyLogger
- it's now referred to by two object variables.
Upvotes: 4
Reputation: 41236
It's actually a lot simpler in C#.
Basically, you can do this:
MyLogger logger = new MyLogger();
MyOtherClass myOtherClass = new MyOtherClass(logger);
MyClass myClass = new MyClass(logger);
In C#, the classes are basically kept around as references (really just pointers under the hood). In this snippet, you are passing the reference to logger
to the constructors of both objects. That reference is the same, so each instance has the same MyLogger
instance.
In this particular instance, you pretty much just need to remove the pointer syntax =D
Upvotes: 22