Reputation: 4119
How does one read a very large JSON file into an array in c# to be split up for later processing?
I have managed to get something working that will:
This was done with the code below but it crashes the program after entering a few lines into the array. This might have to do with the file size.
// If the file extension was a jave file the following
// load method will be use else it will move on to the
// next else if statement
if (fileExtension == ".json")
{
int count = 0;
int count2 = 0;
int inOrOut = 0;
int nRecords=1;
JsonTextReader reader = new JsonTextReader(new StreamReader(txtLoaction.Text));
string[] rawData = new string[5];
while (reader.Read())
{
if (reader.Value != null)
if (inOrOut == 1)
{
if (count == 6)
{
nRecords++;
Array.Resize(ref rawData, nRecords);
//textBox1.Text += "\r\n";
count = 0;
}
rawData[count2] += reader.Value + ","; //+"\r\n"
inOrOut = 0;
count++;
if (count2 == 500)
{
MessageBox.Show(rawData[499]);
}
}
else
{
inOrOut = 1;
}
}
}
A snippet of the JSON I am working with is:
[
{ "millis": "1000",
"stamp": "1273010254",
"datetime": "2010/5/4 21:57:34",
"light": "333",
"temp": "78.32",
"vcc": "3.54" },
]
I need the values out of this JSON. For example, I need "3.54", but I would not want it to print the "vcc".
How can one read a JSON file in and only extract the data needed to be put into an array?
Upvotes: 410
Views: 1230129
Reputation: 113
Very Easiest way I found on online to work with .JSON file in C#(or any other Programming Language)
Prerequisite:-
and here is the URL -> https://app.quicktype.io/
Steps
1> go to this URL - https://app.quicktype.io/
2> Copy and Paste your JSON file structure into Left sidebar
3> Select required Language (here C#) from Options menu
4> Copy generated code and go to your Project and Create a new .cs file with the same name(here "Welcome.cs")
5> Paste all generated code into the newly created class.
6> that's it. :)
Steps to Access value
1> Go to Main Program .cs file or wherever you need to access it.
class Program
{
static void Main(string[] args)
{
Console.WriteLine("Access Json values using Keys.>");
String jsonString = new StreamReader("give <.json> file Path here").ReadToEnd();
// use below syntax to access JSON file
var jsonFile = Welcome.FromJson(jsonString);
string FileName = jsonFile.File;
long Lvl = jsonFile.Level;
bool isTrue = jsonFile.CSharp;
Console.WriteLine(FileName);//JSON
Console.WriteLine(Lvl);//1
Console.WriteLine(isTrue);//true
}
}
Upvotes: 11
Reputation: 6332
With Cinchoo ETL, an open source library, parsing of very large JSON file is iterative and simple to use
1. Dynamic Method: - No POCO class required
string json = @"
[
{
""millis"": ""1000"",
""stamp"": ""1273010254"",
""datetime"": ""2010/5/4 21:57:34"",
""light"": ""333"",
""temp"": ""78.32"",
""vcc"": ""3.54""
},
{
""millis"": ""2000"",
""stamp"": ""1273010254"",
""datetime"": ""2010/5/4 21:57:34"",
""light"": ""333"",
""temp"": ""78.32"",
""vcc"": ""3.54""
}
]
";
using (var r = ChoJSONReader.LoadText(json))
{
foreach (var rec in r)
Console.WriteLine(rec.Dump());
}
Sample fiddle: https://dotnetfiddle.net/mo1qvw
2. POCO Method:
Define POCO class matching json attributes
public class Item
{
public int Millis { get; set; }
public string Stamp { get; set; }
public DateTime Datetime { get; set; }
public string Light { get; set; }
public float Temp { get; set; }
public float Vcc { get; set; }
}
Then using the parser to load the JSON as below
string json = @"
[
{
""millis"": ""1000"",
""stamp"": ""1273010254"",
""datetime"": ""2010/5/4 21:57:34"",
""light"": ""333"",
""temp"": ""78.32"",
""vcc"": ""3.54""
},
{
""millis"": ""2000"",
""stamp"": ""1273010254"",
""datetime"": ""2010/5/4 21:57:34"",
""light"": ""333"",
""temp"": ""78.32"",
""vcc"": ""3.54""
}
]
";
using (var r = ChoJSONReader<Item>.LoadText(json))
{
foreach (var rec in r)
Console.WriteLine(ChoUtility.Dump(rec));
}
Sample fiddle: https://dotnetfiddle.net/fRWu0w
Disclaimer: I'm author of this library.
Upvotes: 0
Reputation: 11
There is an easier way to get JSON from file or from the Web: Json.Net.Curl
Install-Package Json.Net.Curl
// get JObject from local file system
var json = Json.Net.Curl.Get(@"data\JObjectUnitTest1.json");
var json = await Json.Net.Curl.GetAsync(@"data\JObjectUnitTest1.json")
// get JObject from Server
var json = await Json.Net.Curl.GetAsync("http://myserver.com/data.json");
Upvotes: 1
Reputation: 454
There is a faster way of parsing json then Json.Net . If you are using .net core 3.0 or up then you can use the System.Text.Json nuget package to serialize or deserialize.
you need to add:
using System.Text.Json
And then you can serialize as:
var jsonStr = JsonSerializer.Serialize(model);
And Deserialize as:
var model = JsonSerializer.Deserialize(jsonStr);
Upvotes: 5
Reputation: 20881
You can just use the built-in System.Text.Json
instead of the 3rd-party Json.NET
. To promote reuse, the JSON-file-reading functionality belongs in its own class and should be generic rather than hard-coded to a certain type (Item
). Here's a full example:
using System;
using System.IO;
using System.Text.Json;
using System.Threading.Tasks;
namespace Project
{
class Program
{
static async Task Main()
{
Item item = await JsonFileReader.ReadAsync<Item>(@"C:\myFile.json");
}
}
public static class JsonFileReader
{
public static async Task<T> ReadAsync<T>(string filePath)
{
using FileStream stream = File.OpenRead(filePath);
return await JsonSerializer.DeserializeAsync<T>(stream);
}
}
public class Item
{
public int millis;
public string stamp;
public DateTime datetime;
public string light;
public float temp;
public float vcc;
}
}
Or, if you prefer something simpler/synchronous:
class Program
{
static void Main()
{
Item item = JsonFileReader.Read<Item>(@"C:\myFile.json");
}
}
public static class JsonFileReader
{
public static T Read<T>(string filePath)
{
string text = File.ReadAllText(filePath);
return JsonSerializer.Deserialize<T>(text);
}
}
Upvotes: 70
Reputation: 381
string jsonFilePath = @"C:\MyFolder\myFile.json";
string json = File.ReadAllText(jsonFilePath);
Dictionary<string, object> json_Dictionary = (new JavaScriptSerializer()).Deserialize<Dictionary<string, object>>(json);
foreach (var item in json_Dictionary)
{
// parse here
}
Upvotes: 19
Reputation: 116178
How about making everything easier with Json.NET?
public void LoadJson()
{
using (StreamReader r = new StreamReader("file.json"))
{
string json = r.ReadToEnd();
List<Item> items = JsonConvert.DeserializeObject<List<Item>>(json);
}
}
public class Item
{
public int millis;
public string stamp;
public DateTime datetime;
public string light;
public float temp;
public float vcc;
}
You can even get the values dynamically
without declaring Item
class.
dynamic array = JsonConvert.DeserializeObject(json);
foreach(var item in array)
{
Console.WriteLine("{0} {1}", item.temp, item.vcc);
}
Upvotes: 705
Reputation: 878
This code can help you:
string _filePath = Path.GetDirectoryName(System.AppDomain.CurrentDomain.BaseDirectory);
JObject data = JObject.Parse(_filePath );
Upvotes: 1
Reputation: 22203
This can also be done in the following way:
JObject data = JObject.Parse(File.ReadAllText(MyFilePath));
Upvotes: 33
Reputation: 1963
Based on @L.B.'s solution, the (typed as Object
rather than Anonymous
) VB code is
Dim oJson As Object = JsonConvert.DeserializeObject(File.ReadAllText(MyFilePath))
I should mention that this is quick and useful for constructing HTTP call content where the type isn't required. And using Object
rather than Anonymous
means you can maintain Option Strict On
in your Visual Studio environment - I hate turning that off.
Upvotes: 16
Reputation: 362
For any of the JSON parse, use the website http://json2csharp.com/ (easiest way) to convert your JSON into C# class to deserialize your JSON into C# object.
public class JSONClass
{
public string name { get; set; }
public string url { get; set; }
public bool visibility { get; set; }
public string idField { get; set; }
public bool defaultEvents { get; set; }
public string type { get; set; }
}
Then use the JavaScriptSerializer (from System.Web.Script.Serialization), in case you don't want any third party DLL like newtonsoft.
using (StreamReader r = new StreamReader("jsonfile.json"))
{
string json = r.ReadToEnd();
JavaScriptSerializer jss = new JavaScriptSerializer();
var Items = jss.Deserialize<JSONClass>(json);
}
Then you can get your object with Items.name or Items.Url etc.
Upvotes: 10
Reputation: 7666
Doing this yourself is an awful idea. Use Json.NET. It has already solved the problem better than most programmers could if they were given months on end to work on it. As for your specific needs, parsing into arrays and such, check the documentation, particularly on JsonTextReader
. Basically, Json.NET handles JSON arrays natively and will parse them into strings, ints, or whatever the type happens to be without prompting from you. Here is a direct link to the basic code usages for both the reader and the writer, so you can have that open in a spare window while you're learning to work with this.
This is for the best: Be lazy this time and use a library so you solve this common problem forever.
Upvotes: 49
Reputation: 7524
For finding the right path I'm using
var pathToJson = Path.Combine("my","path","config","default.Business.Area.json");
var r = new StreamReader(pathToJson);
var myJson = r.ReadToEnd();
// my/path/config/default.Business.Area.json
[...] do parsing here
Path.Combine uses the Path.PathSeparator and it checks whether the first path has already a separator at the end so it will not duplicate the separators. Additionally, it checks whether the path elements to combine have invalid chars.
See https://stackoverflow.com/a/32071002/4420355
Upvotes: 5