CODEWITHSUNDEEP
php
Kathiravan
Kathiravan

Reputation: 699

PHP remove the word next to search string

i need to remove the next word of search string.. i have search array like array('aa','bb','é');

This is my paragraph 'Hello, this is a test paragraph aa 123 test bb 456'.

In this paragraph i need to remove 123 and 456.

$pattern        = "/\bé\b/i";
$check_string       = preg_match($pattern,'Hello, this is a test paragraph aa 123 test é 456');

How to get the next word?? Please help.

Upvotes: 4

Views: 214

Answers (2)

Madara's Ghost
Madara's Ghost

Reputation: 174957

Here's my solution:

<?php

//Initialization
$search = array('aa','bb','é');
$string = "Hello, this is a test paragraph aa 123 test bb 456";

//This will form (aa|bb|é), for the regex pattern
$search_string = "(".implode("|",$search).")";

//Replace "<any_search_word> <the_word_after_that>" with "<any_search_word>"
$string = preg_replace("/$search_string\s+(\S+)/","$1", $string);

var_dump($string);

You replace "SEARCH_WORD NEXT_WORD" with "SEARCH_WORD", thus eliminating "NEXT_WORD".

Upvotes: 2

arkascha
arkascha

Reputation: 42895

You can simply use phps preg_replace() function for this: 

#!/usr/bin/php
<?php

// the payload to process
$input = "Hello, this is a test paragraph aa 123 test bb 456 and so on.";

// initialization   
$patterns = array();
$tokens   = array('aa','bb','cc');

// setup matching patterns 
foreach ($tokens as $token)
  $patterns[] = sprintf('/%s\s([^\s]+)/i', $token);


// replacement stage
$output = preg_replace ( $patterns, '', $input );

// debug output
echo "input: ".$input."\n"; 
echo "output:".$output."\n";

?>

Upvotes: 0

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