Brandon Miller
Brandon Miller

Reputation: 2297

Can you 'overload a cast' in C++ OOP?

Well, the WinAPI has a POINT struct, but I am trying to make an alternative class to this so you can set the values of x and y from a constructor. This is hard to explain in one sentence.

/**
 * X-Y coordinates
 */
class Point {
  public:
    int X, Y;

    Point(void)            : X(0),    Y(0)    {}
    Point(int x, int y)    : X(x),    Y(y)    {}
    Point(const POINT& pt) : X(pt.x), Y(pt.y) {}

    Point& operator= (const POINT& other) {
        X = other.x;
        Y = other.y;
    }
};

// I have an assignment operator and copy constructor.
Point myPtA(3,7);
Point myPtB(8,5);

POINT pt;
pt.x = 9;
pt.y = 2;

// I can assign a 'POINT' to a 'Point'
myPtA = pt;

// But I also want to be able to assign a 'Point' to a 'POINT'
pt = myPtB;

Is it possible to overload operator= in a way so that I can assign a Point to a POINT? Or maybe some other method to achieve this?

Upvotes: 3

Views: 122

Answers (3)

juanchopanza
juanchopanza

Reputation: 227400

You could add a cast operator to your Point class:

class Point {
  // as before
  ....
  operator POINT () const { 
    // build a POINT from this and return it
    POINT p = {X,Y};
    return p;
  }
}

Upvotes: 4

Denis Ermolin
Denis Ermolin

Reputation: 5546

Use conversion operator:

class Point 
{
public:
   operator POINT()const
   {
       Point p;
       //copy data to p
       return p;
   }
};

Upvotes: 0

Mankarse
Mankarse

Reputation: 40603

This is the job of a type conversion operator:

class Point {
  public:
    int X, Y;

    //...

    operator POINT() const {
        POINT pt;
        pt.x = X;
        pt.y = Y;
        return pt;
    }
};

Upvotes: 4

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