Troy Mitchel
Troy Mitchel

Reputation: 1810

Swap controls in TableLayoutPanel Visual Studio

I have a need to swap controls in a TableLayoutPanel. They are in separate rows. I've tried the suggested code but to no avail. Is there a solution this other than removing all the controls and re adding? The answer can be in C# or VB.

Private Sub Button2_Click(sender As System.Object, e As System.EventArgs) Handles Button2.Click
    Dim c1 As Control = Me.tlp.GetControlFromPosition(0, 0)
    Dim c2 As Control = Me.tlp.GetControlFromPosition(0, 1)

    If c1 IsNot Nothing And c2 IsNot Nothing Then
        Me.tlp.SetRow(c2, 0)
        Me.tlp.SetRow(c1, 1)
    End If

End Sub

Upvotes: 6

Views: 3257

Answers (4)

user5296899
user5296899

Reputation: 1

Same in C# code: swapping / exchanging controls at any positions 1 and 2:

private void SwapControls(TableLayoutPanel tlp, TableLayoutPanelCellPosition cpos1, TableLayoutPanelCellPosition cpos2)
{
    var ctl1 = tlp.GetControlFromPosition(cpos1.Column, cpos1.Row);
    var ctl2 = tlp.GetControlFromPosition(cpos2.Column, cpos2.Row);
    if (ctl1 != null) // position1 can be empty
        tlp.SetCellPosition(ctl1, cpos2);
    if (ctl2 != null) // position2 can be empty
        tlp.SetCellPosition(ctl2, cpos1);
}

Sample of usage:

SwapControls(TableLayoutPanel1, new TableLayoutPanelCellPosition(0, 0), new TableLayoutPanelCellPosition(1, 0))

Upvotes: 0

Troy Mitchel
Troy Mitchel

Reputation: 1810

After searching around for a day and not coming up with nothing I finally took a shot in the dark and found the answer. You need to use the SetChildIndex of the control in the table. See Below...

Note: this only works if you add controls to TableLayoutPanel without row or column index.

Private Sub Form1_Load(sender As System.Object, e As System.EventArgs) Handles MyBase.Load
    tlp.RowStyles.Clear()
    For i As Integer = 0 To 4
        Dim txt As New TextBox
        txt.Text = i
        txt.Name = "txt" & i
        tlp.Controls.Add(txt) 'this works
        'tlp.Controls.Add(txt, 0, i) 'this will not work when button is clicked
    Next
End Sub

Private Sub Button2_Click(sender As System.Object, e As System.EventArgs) Handles Button2.Click
    Dim c1 As Control = Me.tlp.GetControlFromPosition(0, 0)
    Dim c2 As Control = Me.tlp.GetControlFromPosition(0, 1)

    If c1 IsNot Nothing And c2 IsNot Nothing Then
        tlp.Controls.SetChildIndex(c1, 1)
        tlp.Controls.SetChildIndex(c2, 0)
    End If

End Sub

Upvotes: -1

Kris.K
Kris.K

Reputation: 1613

If you have fixed length TableLayoutPanel, you may use FlowLayoutPanel (then length of it controls must have equal FlowLayoutPanel length):

Dim c1 As Control = Button1
Dim c2 As Control = CheckBox1

Dim i1 = FlowLayoutPanel1.Controls.IndexOf(c1)
Dim i2 = FlowLayoutPanel1.Controls.IndexOf(c2)

FlowLayoutPanel1.Controls.SetChildIndex(c1, i2)
FlowLayoutPanel1.Controls.SetChildIndex(c2, i1)

Upvotes: 0

Victor Zakharov
Victor Zakharov

Reputation: 26454

Here is the code to swap controls in a TableLayoutPanel - you have two options.

1) Swap by reference to controls:

Private Sub SwapControls(tlp As TableLayoutPanel, ctl1 As Control, ctl2 As Control)
  Dim ctl1pos As TableLayoutPanelCellPosition = tlp.GetPositionFromControl(ctl1)
  tlp.SetCellPosition(ctl1, tlp.GetPositionFromControl(ctl2))
  tlp.SetCellPosition(ctl2, ctl1pos)
End Sub

It does not depend on where controls are located in TableLayoutPanel - could be different rows, columns or both.

Sample usage:

SwapControls(TableLayoutPanel1, Button1, Button2)

2) Swap by column/row index:

Private Sub SwapControls(tlp As TableLayoutPanel, pos1 As TableLayoutPanelCellPosition, pos2 As TableLayoutPanelCellPosition)
  Dim ctl1 As Control = tlp.GetControlFromPosition(pos1.Column, pos1.Row)
  Dim ctl2 As Control = tlp.GetControlFromPosition(pos2.Column, pos2.Row)
  SwapControls(tlp, ctl1, ctl2)
End Sub

Sample usage:

SwapControls(TableLayoutPanel1, New TableLayoutPanelCellPosition(0, 0), New TableLayoutPanelCellPosition(1, 0))

Solutions are based around TableLayoutPanel.SetRow help article on MSDN and some research on its decompiled representation. Both were tested and deemed working.

Upvotes: 6

Related Questions